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2 years ago

24- Which of the fallowing devices make use a lens

Physics

2 answers:

mezya [45]2 years ago

6 0

Answer:

Explanation:

all because the projector is a lens and the magnifying also the microscope

Luda [366]2 years ago

5 0

Answer would be D because they all use it

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A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are

irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

$s=u*t+\frac{1}{2} (a*t^2)$

$1=0*t+\frac{1}{2} (6.54*t^2)$

t = 0.553 seconds

4 0

3 years ago

Two cars are traveling along perpendicular roads, car A at 40 mi/hr, car B at 60 mi/hr. At noon, when car A reaches the intersec

Serggg [28]

Answer:

$\frac{dD}{dt} = -4 miles/hour$

negative sign indicates that the distance is decreasing with time

Explanation:

Let at any time t after noon that is 12 p.m.

distance traveled by car A = 40t

distance traveled by car B = 90-60t

then distance between the two cars at time t

$D^2= (40t)^2+(90-60t)^2$ ............1

also, at time 1 p.m.

distance $D^2= (40\times1)^2+(90-60\times1)^2$

D=50 Km

differentiating equation 1 w.r.t. t we get

$2D\frac{dD}{dt}= 2\times40t\times40+2(90-60t)(-60)$

put t= 1 and D= 50 we get

$2\times50\frac{dD}{dt}= 3200\times1-3600\times1$

$\frac{dD}{dt} = -4 miles/hour$

3 0

2 years ago

A pipe open at both ends has a fundamental frequency of 220 Hz when the temperature is 0°C. (a) What is the length of the pipe?

Allushta [10]

Explanation:

It is given that,

Fundamental frequency, f = 220 Hz

(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.

For open pipe, $\lambda=2l$

l is the length of pipe

Also,

$v=f\lambda$

$l=\dfrac{v}{2f}=\dfrac{331}{2\times 220}=0.75\ m$

(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.

$v'=331\sqrt{1+\dfrac{T}{273}}$

$v'=331\sqrt{1+\dfrac{30}{273}}$

v' = 348.71 m/s

So, $f'=\dfrac{v'}{\lambda}$

$f'=\dfrac{348.71}{2\times 0.75}$

f' = 232.4 Hz

Hence, this is the required solution.

8 0

2 years ago

Read 2 more answers

A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object?

hichkok12 [17]

Hello!

A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object ?

Data:

F (force) = 5 N

m (mass) = ?

a (acceleration) = 2 m/s²

Solving:

$F = m*a$

$5 = m*2$

$2\:m = 5$

$m = \dfrac{5}{2}$

$\boxed{\boxed{m = 2.5\:kg}}\end{array}}\qquad\quad\checkmark$

Answer:

2.5 kg

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

7 0

2 years ago

A chemical equation where the number of atoms of each element are the same on both sides. Coefficients are often needed to balan

rusak2 [61]

Answer:

A balanced equation

Explanation:

when atoms of various elements or compounds react, they do this in mole ratio. It is a law to always balance the number of elements of each element on the reactant side to the corresponding elements on the product side of the equation. This is done by the introduction of coefficients.

6 0

2 years ago

Read 2 more answers