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vova2212 [387]
3 years ago
13

There is a hydraulic system that by means of a 5 cm diameter plunger to which a 5 N force is applied and that force is transmitt

ed by means of a fluid to a 1 meter diameter plunger. Determine how much force can be lifted by the 1 m diameter plunger,
1) - 234 N
2) - 800 N
3) - 636 N
4) - 600 N
Physics
1 answer:
KengaRu [80]3 years ago
4 0

Explanation:

Pressure is the same for both plungers.

P = P

F / A = F / A

F / (¼ π d²) = F / (¼ π d²)

F / d² = F / d²

5 N / (0.05 m)² = F / (1 m)²

F = 2000 N

None of the options are correct.

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Answer with Explanation:

We are given that

Angle of incidence,i=30^{\circ}

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We know that

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n_2=\frac{n_1sin i}{sin r}=\frac{sin30}{sin19.24}=1.517

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Wavelength in the solution,\lambda'=\frac{\lambda}{n_2}

\lambda'=\frac{632.8}{1.517}=417nm

c.Frequency does not change .It remains same in vacuum and solution.

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Frequency,\nu=4.74\times 10^{14}Hz

d.Speed in the solution,v=\frac{c}{n_2}

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The average velocity of blood flowing in a certain 4-mm-diameter artery in the human body is 0.28 m/s. The viscosity and density
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Answer:

V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s

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V = Volume flow rate = ?

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