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3 years ago

X^2 -9 = -15 i got decimals please help me

2 answers:

7 0

Equation: x² - 9 = -15

Step-by-step solution:

• Move -9 to right side
-> x² = -15 + 9

• Solve
-> x² = -6

• Root of both sides
-> x = √-6
This is wrong because √-1 = imaginary number and it doesn't look like you're dealing with imaginary numbers so check the equation again

olga nikolaevna [1]3 years ago

4 0

Answer:

sqrt 24

Step-by-step explanation:

x^2-9=-15

x^2-9+9=-15+9

x^2=24

x=sqrt 24

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KatRina [158]

Answer:

Container $\rm X$ will have less label area than container $\rm Y$ by about $9\; \rm in$ .

Step-by-step explanation:

A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.

Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of $h$ and a radius of $r$ at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width $h$ and length $2\,\pi\, r$ .

Apply this reasoning to both cylinder $\mathrm{X}$ and $\rm Y$ :

For cylinder $\mathrm{X}$ , $h = 6\; \rm in$ while $r = 4.5\; \rm in$ . Therefore, when the lateral side of this cylinder is unrolled:

The width of the rectangle will be $6\; \rm in$ , while
The length of the rectangle will be $2 \, \pi \times 4.5\; \rm in = 9\, \pi\; \rm in$ .

That corresponds to a lateral surface area of $54\, \pi\; \rm in^2$ .

For cylinder $\rm Y$ , $h = 10.5\; \rm in$ while $r = 3\; \rm in$ . Similarly, when the lateral side of this cylinder is unrolled:

The width of the rectangle will be $10.5\; \rm in$ , while
The length of the rectangle will be $2\pi\times 3\; \rm in = 6\,\pi \; \rm in$ .

That corresponds to a lateral surface area of $63\,\pi \; \rm in^2$ .

Therefore, the lateral surface area of cylinder $\rm X$ is smaller than that of cylinder $\rm Y$ by $9\,\pi\; \rm in^2$ .

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3 years ago

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nasty-shy [4]

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3 years ago

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expeople1 [14]

Answer:

7.3

Step-by-step explanation:

For this question, you must use the distance formula. The distance formula is based around Pythagorean Theorem, so you will see some similarities.

Distance = $\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}$

X2 is 7 (X coordinate of school)

X1 is 5 (X coordinate of friend's house)

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2 years ago

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A boat crew rowed 10.5 miles downstream, with the current, in 1.5 hours. the return trip upstream , against the current , covere

alukav5142 [94]

Answer:

The speed of the boat is 5 miles per hours

The speed of the current is 2 miles per hours .

Step-by-step explanation:

Given as :

The distance cover by boat downstream = D = 10.5 miles

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The distance cover by boat Upstream = d = 10.5 miles

The time taken by boat to cover d distance = t = 3.5 hours

Let The speed of boat = x mph

Let The speed of current = mph

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∵ Speed = $\dfrac{Distance}{Time}$

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Or, x + y = 7 .......A

For Upstream

x - y = $\dfrac{d}{t}$

Or, x - y = $\dfrac{10.5}{3.5}$

Or, x - y = 3 .......B

Now, Solving eq A and eq B

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Or, 2 x + 0 = 10

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i.e x = 5 mph

So, The speed of the boat = x = 5 miles per hours

Put the value of x into eq A

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∴ y = 7 - 5

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3 years ago