The simplest way is to make for loop first you need to<span> generate 1,2,4,8,16,32,64,128,256....and others number in Array. Then you will check every number. Like this.</span>
<span>Decimal </span>Input 84;
64 is closest to 84.
84-64=20
<span>Write: </span>1
20-32=-12(Because It's negative you will write 0)
Write:10
20-16=4
<span>Write: </span>101
4-8=-4 (Negative)
Write:1010
4-4=0
<span>Write: </span>10101
0-2=-2
0-1=-1
<span>Write: </span><span>1010100 = 84</span>
It think it's a Nested List.
Im so sorry if this is wrong
Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Answer:
Explanation:
See the attached picture for answer.
