Question

The radius of a hailstone varies directly with

Answer 1

Answer:

Hailstone remained in the cloud for 25 seconds.

Step-by-step explanation:

Radius of a hailstone varies directly with the duration for which it was in the cloud.

Let the radius of the hailstone is 'r' and it was in the cloud for 't' seconds.

r ∝ t

r = kt [ k is the proportionality constant]

If r = 0.5 inches and t = 10 seconds

Then, 0.5 = k × 10

k = $\frac{0.5}{10}$

k = 0.05

Now we have to find the duration t for which hailstone was in the cloud having radius = 1.25 inches.

1.25 = 0.05 × t

t = $\frac{1.25}{0.05}$

t = 25 second

Therefore, hailstone remained in the cloud for 25 seconds.