The complete question in the attached figure

Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]

[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft

[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft

the answer Part A) is
the perimeter of the garden is 37.85 ft

Part B) Find the area of the garden

[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]

[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²

[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²

the answer Part B) is
the Area of the garden is 69.625 ft²

8 0

3 years ago

Find the area of the triangle

maks197457 [2]

Answer:

12 yd^2 (c)

Step-by-step explanation:

A=1/2bh

= 1/2 x 8 x 3

=12 yd^2

Hope it helps!!!

4 0

2 years ago

Read 2 more answers

Use order of operations to make this true 7 11 4 2 = 10

Keith_Richards [23]

Answer:

$7 + 11 - 4 \times 2 = 10$

Step-by-step explanation:

Using order of operations, the first thing to be calculated would be $4 \times 2$ .

That would turn our equation into this:

$7 + 11 - 8 = 10$

You can then calculate left-to-right as usual to get the answer 10.

5 0

3 years ago

Verify the following <br> i.[ -3/4]3 = -27/64<br> ii. [-2/3]6 = 64/ 729

Juliette [100K]

Answer:

The relationships are correct and valid

Step-by-step explanation:

The correct question is as follows;

Verify the following

i.[ -3/4]^3 = -27/64

ii. [-2/3]^6 = 64/ 729

We have the solution as follows;

i) we have;

(-3/4)^3

That means ;

-3^3 = -3^3 = -27

4^3 = 64

so;

(-3/4)^3 = -27/64

ii) (-2/3)^6

(-2)^6 = 64

3^6 = 729

Thus;

(-2/3)^6 = 64/729

4 0

3 years ago