y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
<u>Answer</u>
3.5 hours.
<u>Explanation</u>
The first step is to calculate the constant of proportionality.
t ∝ 1/n
t = k/n Where t = time, K= constant and n = number of people
t = k/n
k =tn
= 5×7 = 35
The equation becomes;
t = 35/n
for n = 10,
t = 35/10
t = 3.5 hours.
Answer:
The greatest number of 15 inches pieces that can be cut from 5 rolls of length 9 feet is: 35
Step-by-step explanation:
Given
Total length of one roll of ribbon = 9 feet
As the pieces have to be cut into inches, we will convert the measurement in feet to inches
As there are 12 inches in one feet, 9 feet will be equal to:
9*12 = 108 inches
Now first of all, we have to see how many 15 inches pieces can be cut from one role
So,

So the seamstress can cut 7 15-inch long pieces from a roll.
Now given that he has to cut from 5 rolls, the total number of 15-inch pieces will be:

Hence,
The greatest number of 15 inches pieces that can be cut from 5 rolls of length 9 feet is: 35