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riadik2000 [5.3K]
3 years ago
13

Which pair of inequalities is shown in the graph?

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

y > x - 5

and

y > -x + 1

Step-by-step explanation:

Since the solution goes above both the lines, we know that the inequalities must have a y > aspect. To get the next portion, simply find the equation of the lines. This would get you y > x - 5 and y > -x + 1.

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
skelet666 [1.2K]
-5t2 + 40t = 0
5t(-t+ 8) = 0
5t = 0 or t = 8
7 0
3 years ago
For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?
sergey [27]

Answer:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}

Step-by-step explanation:

Given

f(x) = \frac{7}{2}x - 16

Required

The difference quotient for h

The difference quotient is calculated as:

\frac{f(x + h) - f(x)}{ h}

Calculate f(x + h)

f(x) = \frac{7}{2}x - 16

f(x+h) = \frac{7}{2}(x+h) - 16

f(x+h) = \frac{7}{2}x+ \frac{7}{2}h- 16

The numerator of \frac{f(x + h) - f(x)}{ h} is:

f(x + h) - f(x) =  \frac{7}{2}x+ \frac{7}{2}h- 16 -(\frac{7}{2}x - 16)

f(x + h) - f(x) =  \frac{7}{2}x+ \frac{7}{2}h- 16 -\frac{7}{2}x + 16

Collect like terms

f(x + h) - f(x) =  \frac{7}{2}x  -\frac{7}{2}x + \frac{7}{2}h- 16 + 16

f(x + h) - f(x) = \frac{7}{2}h

So, we have:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h \div h

Rewrite as:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h * \frac{1}{h}

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}

5 0
2 years ago
Help ill give brainlest pls
N76 [4]

Answer:

Step-by-step explanation:

B is the answer pretty sure

8 0
2 years ago
Read 2 more answers
I really need help thia is my last chance to get a good grade in math-​
romanna [79]

Answer:

Step-by-step explanation:

bsahaahaaana

8 0
2 years ago
Which expression is equivalent to
noname [10]

Answer:

3/5 m^2 n^3

Step-by-step explanation:

√225 = 15

√625 = 25

√m^4 = m^2

√n^6 = n^3

Put it all together and you get 15/25 m^2 n^3

Simplify 15/25 to 3/5

4 0
3 years ago
Read 2 more answers
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