The molecules doesn't need energy to cross through.
The diffusion doesn't need protien, the molecules pass between phospholipids by passes protien. It moves smaller molecules. Facilitated need protien also hormone, and larger molecules.
I wish it makes sense.
The concentration of lipids necessary to prepare liposomes with a diameter of 250 nm is 0.30 mM.
<h3>What are liposomes?</h3>
Liposomes are vesicles which are made up of a lipid bilayer membrane.
Liposomes are important as delivery vehicles for substances such as drugs.
Ultrasonication is a method of liposomes preparation.
Solution of liposomes is dependent on the size.
The larger the diameter, the smaller the l elution volume. Also, increasing lipid concentration will decreases elution volume.
Therefore, the concentration of lipids necessary to prepare liposomes with a diameter of 250 nm is 0.30 mM.
Learn more about liposomes at: brainly.com/question/15852922
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Answer:
A) Hummingbirds drinking nectar from a plant.
Step-by-step explanation:
Here are some examples of natural selection: In a habitat there are red bugs and green bugs. The birds prefer the taste of the red bugs, so soon there are many green bugs and few red bugs. The green bugs reproduce and make more green bugs and eventually there are no more red bugs.
10000000 km per second which is really fast lol
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
