Answer:
kilograms
Explanation:
hope this helps, pls mark brainliest :D
Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.
Be sure your answer has the correct number of significant digits.
Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L
Explanation:
According to ideal gas equation:

P = pressure of gas = 1 atm (at STP)
V = Volume of gas = 3.16 L
n = number of moles = ?
R = gas constant =
T =temperature =



According to stoichiometry:
4 moles of chlorine produces = 1 mole of carbon tetrachloride
Thus 0.141 moles of methane produces =
moles of carbon tetrachloride
volume of carbon tetrachloride =
Thus volume of carbon tetrachloride that would be produced is 0.788 L
Answer:
Ne 20: 10
and
Ne 22: 12
Explanation:
Ne-20:
N = A - Z = 20 - 10 = 10 neutrons
Ne-22:
N = A - Z = 22 - 10 = 12 neutrons
N: number of neutrons
A: mass number
Z: atomic number
Answer: The water (in a subtle sort of way) will now be attracted towards the balloon
I attached a picture to help make sense
Answer:
10 moles de NO2
Explanation:
Tenemos la ecuación de la reacción como sigue;
N2 (g) + 2 O2 (g) → 2 NO2 (g)
Asi que;
Si 1 mol de nitrógeno produce 2 moles de NO2
5 moles de nitrógeno producirán 5 * 2/1 = 10
Por tanto, se producen 10 moles de NO2 moles