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3 years ago

What is the range of y= sin ø

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

The range would be (-1,1).

Hope this helps! (:

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Booker has 85 video games. He has 3 shelves to put the video games on. Each shelf can hold 40 games. How many more video games d

iris [78.8K]

Multiply 40 * 3 to find how many video games his shelves can hold (120).
Subtract 85 from 120 to find how many more video games he has room for.

3 0

3 years ago

Read 2 more answers

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1+

egoroff_w [7]

Answer:

$a=\frac{3\times 7}{7}+\frac{12}{7}$ (First step for obtaining a common denominator for the two fraction)

$a=\frac{33}{7}\text{ m/s}^2$

Step-by-step explanation:

$\text{Given Expression: }a=a_1+\frac{F}{m}$

where,

a is acceleration of an object.(Need to calculate)

$a_1=3.00\text{ m/s}^2$

$F=12.0\text{ Kg.m/s}^2$

$m=7.00\text{ kg}$

$\text{Substitute }a_1, \text{ F, and m into expression and we get}$

$a=3+\frac{12}{7}$

Now we will simplify above expression for a

First we make common denominator.

Common denominator is 7. So, we make both denominator 7. We multiply by 7 at top and bottom with 3. We get

$a=\frac{3\times 7}{7}+\frac{12}{7}$ (First step for obtaining a common denominator for the two fraction)

Now we combine the numerator

$a=\frac{21+12}{7}$

$a=\frac{33}{7}\text{ m/s}^2$

3 0

3 years ago

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The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class

alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.