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miv72 [106K]
3 years ago
12

How is wavelength related to a waves energy?

Physics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

The energy of a wave is directly proportional to its frequency, but inversely proportional to its wavelength. In other words, the greater the energy, the larger the frequency and the shorter (smaller) the wavelength.

Explanation:

i hope it will help u buddy✅

LuckyWell [14K]3 years ago
8 0

Answer:

The energy of a wave is directly proportional to its frequency, but inversely proportional to its wavelength. In other words, the greater the energy, the larger the frequency and the shorter (smaller) the wavelength.

Explanation:

._.

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How do Swati and Banks adjust their body position during a skydiving jump so they can fall at the same rate?
Wittaler [7]

Sky diving involves free fall under gravity along with the drag due to air molecules pushing against the body slowing the rate of fall of a body. This is actually a significant amount of force.  The drag force depends on the contact surface area and weight of the body. More the surface area in contact, more would be the drag. The sitting position of the skydiver would experience less drag than the chest down position. This is because of the less contact surface area of the body with the air molecules while in the former case. Since no two persons have identical body shape and weight, the rate of fall can be made nearly equal but not exactly equal. This is would be possible when they are having same body position.

3 0
3 years ago
In a crash test, a car with a mass of 1600 kg is initially moving at a speed of 20 m/s just before it collides with a barrier. T
Andrews [41]

Answer:

The answer to the given points can be defined as follows:

Explanation:

In point 1:

\bold{v_f^2=  v_i^2+2as}\\\\\to v_f=0\\\\\to v_i=20 \frac{m}{s}\\\\\to s= 4.50\ m -3.60 \ m \\\\

      =0.9 \ m \\

put the value in the above formula:

\to 0=  20^2+2 \times a \times 0.9\\\\\to -1.8\ a=400\\\\\to -a= \frac{400}{1.8} \\\\ \to a= -222.22\ \  \frac{m}{s^2}

 \bold{v_f=v_i+at}\\\\\to 0=20+ (-222.22)t\\\\\to  222.22t=20\\\\\to t=\frac{20}{222.22}\\\\\to t= 0.0900 \ s\\\\\to v_{avg}=\frac{s}{t}=\frac{0.9}{t}= 10\ \frac{m}{s}

for point 2:

t= 0.0900 \ s  -\text{found above}

for point 3:

\to |a| = 222.22 \frac{m}{s^2} \text{found above}\\\\\to \bold{|F| = m \cdot |a|}\\\\

         =1600 \ kg \times 222.22 \ \frac{m}{s^2} \\\\= 3.55\times 10^{5} \ N

5 0
3 years ago
The speed of light waves is?
denpristay [2]

Answer:

299,792,458 metres per second

Explanation:

3 0
3 years ago
In 5 meters, a person running at 0.8 m/s accelerates at 1.6 m/s2. How fast 16 points
frutty [35]

They were going at a velocity 4.07m/s

<u>Explanation:</u>

Distance s =5 m

initial velocity u= 0.8 m/s

Acceleration a =1.6m/s2

We have to calculate the velocity with which they were going afterwards i.e final velocity.

Use the equation of motion

v^2=u^2+2as\\=0.8^2+2\times 1.6\times 5\\=16.64\\v=4.07 m/s

They were going with a velocity 4.07 m/s afterwards.

5 0
3 years ago
Help me please, help
Alisiya [41]

Answer:

455,000 Pa

Explanation:

PV = nRT

If n is constant:

PV / T = PV / T

(101,325 Pa) (718 mL) / (273 K) = P (175 mL) / (26 + 273) K

P = 455,000 Pa

6 0
4 years ago
Read 2 more answers
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