Sky diving involves free fall under gravity along with the drag due to air molecules pushing against the body slowing the rate of fall of a body. This is actually a significant amount of force. The drag force depends on the contact surface area and weight of the body. More the surface area in contact, more would be the drag. The sitting position of the skydiver would experience less drag than the chest down position. This is because of the less contact surface area of the body with the air molecules while in the former case. Since no two persons have identical body shape and weight, the rate of fall can be made nearly equal but not exactly equal. This is would be possible when they are having same body position.
Answer:
The answer to the given points can be defined as follows:
Explanation:
In point 1:
put the value in the above formula:


for point 2:
for point 3:


Answer:
299,792,458 metres per second
Explanation:
They were going at a velocity 4.07m/s
<u>Explanation:</u>
Distance s =5 m
initial velocity u= 0.8 m/s
Acceleration a =1.6m/s2
We have to calculate the velocity with which they were going afterwards i.e final velocity.
Use the equation of motion

They were going with a velocity 4.07 m/s afterwards.
Answer:
455,000 Pa
Explanation:
PV = nRT
If n is constant:
PV / T = PV / T
(101,325 Pa) (718 mL) / (273 K) = P (175 mL) / (26 + 273) K
P = 455,000 Pa