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3 years ago

How is wavelength related to a waves energy?

Physics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Answer:

The energy of a wave is directly proportional to its frequency, but inversely proportional to its wavelength. In other words, the greater the energy, the larger the frequency and the shorter (smaller) the wavelength.

Explanation:

i hope it will help u buddy✅

LuckyWell [14K]3 years ago

8 0

Answer:

Explanation:

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What are scientific theories?

Goryan [66]

A scientific theory is an explanation of an aspect of the natural world that can be repeatedly tested and verified in accordance with the scientific method, using accepted protocols of observation, measurement, and evaluation of results. Where possible, theories are tested under controlled conditions in an experiment.

8 0

3 years ago

The sound level at a distance of 1.48 m from a source is 120 dB. At what distance will the sound level be 70.7 dB?

Tju [1.3M]

Answer:

The second distance of the sound from the source is 431.78 m..

Explanation:

Given;

first distance of the sound from the source, r₁ = 1.48 m

first sound intensity level, I₁ = 120 dB

second sound intensity level, I₂ = 70.7 dB

second distance of the sound from the source, r₂ = ?

The intensity of sound in W/m² is given as;

$dB = 10 Log[\frac{I}{I_o} ]\\\\For \ 120 dB\\\\120 = 10Log[\frac{I}{1*10^{-12}}]\\\\12 = Log[\frac{I}{1*10^{-12}}]\\\\10^{12} = \frac{I}{1*10^{-12}}\\\\I = 10^{12} \ \times \ 10^{-12}\\\\I = 1 \ W/m^2$

$For \ 70.7 dB\\\\70.7 = 10Log[\frac{I}{1*10^{-12}}]\\\\7.07 = Log[\frac{I}{1*10^{-12}}]\\\\10^{7.07} = \frac{I}{1*10^{-12}}\\\\I = 10^{7.07} \ \times \ 10^{-12}\\\\I = 1 \times \ 10^{-4.93} \ W/m^2$

The second distance, r₂, can be determined from sound intensity formula given as;

$I = \frac{P}{A}\\\\I = \frac{P}{\pi r^2}\\\\Ir^2 = \frac{P}{\pi }\\\\I_1r_1^2 = I_2r_2^2\\\\r_2^2 = \frac{I_1r_1^2}{I_2} \\\\r_2 = \sqrt{\frac{I_1r_1^2}{I_2}} \\\\r_2 = \sqrt{\frac{(1)(1.48^2)}{(1 \times \ 10^{-4.93})}}\\\\r_2 = 431.78 \ m$

Therefore, the second distance of the sound from the source is 431.78 m.

7 0

3 years ago

What is a living organism? Give a few examples.

zhuklara [117]

Answer:

It's a individual form of life. Examples of this are bacterium , protists and fungus

7 0

3 years ago

A vacuum gage connected to a chamber reads 39 kPa at a location where the atmospheric pressure is 92 kPa. Determine the absolute

Nata [24]

Answer: 53 kPa

Explanation:

Absolute pressure is a pressure value referred to absolute zero or vacuum. This value indicates the total pressure to which a body or system (the chamber in this situation) is subjected, considering the total pressure acting on it.

In this sense, the equation that will be useful in this case is:

$P_{atmospheric}= P_{absolute} + P_{vacuum}$ (1)

Where:

$P_{atmospheric}=92 kPa$ is the atmospheric pressure

$P_{vacuum}=39 kPa$ is the vacuum pressure

$P_{absolute}$ is the absolute pressure

Isolating $P_{absolute}$ from (1):

$P_{absolute}=P_{atmospheric} - P_{vacuum}$ (2)

$P_{absolute}=92 kPa - 39 kPa$ (3)

Finally:

$P_{absolute}=53 kPa=53(10)^{3} Pa$ This is the absolute pressure in the chamber

7 0

4 years ago

An echo repeats two syllables.If the velocity of sound is 330 m/s , then the distance of the reflecting surface is-

Andreas93 [3]

<span>Well, the main point you should remember is that we only can hear 20hz that leads to T=0.05sec which means that the distance leads us to velocity x time.
When calculating, you get 330 * 0.05=16.5 .
The number which you got from the previous step has to me multiplied 4 times (4 minutes) and you will get the answer you need - </span><span>a) 66.0 m.
Do hope it will help you! Regards!</span>

6 0

4 years ago