Elements is the answer to this question
Answer:
It continue to move forward at a constant velocity which will be slower than before the front thruster was fired.
Explanation:
Before the front thruster was fired, the spacecraft was already moving at a particular velocity.
After the malfunction, the front thruster is fired and then the force exerted by that front thruster slows the spacecraft down, as we are told.
By using the rear thruster to exert a force equal to that from the front thrusters, a force equal in magnitude to that of the front thrusters is added, cancelling out the effect of the front thrusters. Because the spacecraft is already moving at a slower speed at this point compared to the beginning, it continues to move at that speed.
Answer:
fr = 65.46 N
, a = 8.74 m / s² and vf = 19.25 m / s
Explanation:
We write a reference system with an axis parallel to the slide and gold perpendicular axis, in this system we decompose the weight
sin 21.2 = Wx / W
cos21.2 = Wy / W
Wx = W sin21.2
Wy = W cos 21.2
We form Newton's equations
X axis
Wx -fr = m a
Y Axis
N- Wy = 0
N = Wy
fr = μ N
fr = μ (W cos 21.2)
fr = 0.113 63.4 9.8 cos 21.2
fr = 65.46 N
We replace and calculate the acceleration
W sin 21.2 - μ W cos 21.2 = m a
a = g (sin21.2 - μ cos 21.2)
a = 9.8 (without 21.2 - 0.113 cos 21.2)
a = 8.74 m / s²
This acceleration is along the slope of the slide, so we can calculate the distance
d = 21.2 m
vf² = v₀² + 2 a d
vf² = 0 + 2 a d
vf = √(2 8.74 21.2)
vf = √ (370,576)
vf = 19.25 m / s
Answer:
I guess the answer was d.The current at P is greater than the current at Q...
