Answer: The rod through induction electroscope through friction
Step-by-step explanation:
The answer to this is
x=8
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
as the product of 90 degrees and 20 degrees
30x60=1800
90x20=1800
Answer:
This uses the method of elimination/addition.
Step-by-step explanation:
1 (9x + 7y = 15)
-7 (5x + y = -9) <— let’s eliminate y for both equations
9x + 7y = 15
+ -35x - 7y = 63 <— add both of the equations
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- 26x + 0y = 6
(Please let me know if the answer is correct or not)
