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german
3 years ago
13

What is the OH- if the oh of a solution is 6.10

Chemistry
1 answer:
-Dominant- [34]3 years ago
5 0

OH - REFERS TO THAT OT IS ION OF BASE IF THE SOLUTION OF BASE HAS PH 6.10 SO IT IS ACIDIC SO IT IS NOT POSSIBLE THAT SOLUTION OF OH- IS PH 6.10

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5 0
3 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

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5 0
3 years ago
g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir
sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

7 0
3 years ago
What happens to particles during<br> changes of state between solids,<br> liquids, and gases?
oksano4ka [1.4K]
Answer:
Their vibrations speed up

Explanation:
They start vibrating faster and faster and start generating more and more heat and separate from each other so, therefore (usually), become less dense
7 0
3 years ago
Read 2 more answers
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