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german
3 years ago
13

What is the OH- if the oh of a solution is 6.10

Chemistry
1 answer:
-Dominant- [34]3 years ago
5 0

OH - REFERS TO THAT OT IS ION OF BASE IF THE SOLUTION OF BASE HAS PH 6.10 SO IT IS ACIDIC SO IT IS NOT POSSIBLE THAT SOLUTION OF OH- IS PH 6.10

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Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t
solniwko [45]
Heart: Pumps blood through the body
Bone: Provides structure
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7 0
3 years ago
Read 2 more answers
Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr
matrenka [14]

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total  moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = 6.023X10^{23}X0.691=4.16X10^{23}

the percentage of heaviest Sn is 5.80%

So the total atoms of Sn^{124} = 5.80% X 4.16X10^{23}

Total atoms of Sn^{124}=2.41X10^{22} atoms

the mass of Sn^{124} will be = \frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g

5 0
3 years ago
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nydimaria [60]
Is the answer Radiation
4 0
2 years ago
Phosphorus-32 is radioactive and has a half life of 14.3 days. What percentage of a sample would be left after 12.6 days
nadya68 [22]

Answer:

There is 54.29 % sample left after 12.6 days

Explanation:

Step 1: Data given

Half life time = 14.3 days

Time left = 12.6 days

Suppose the original amount is 100.00 grams

Step 2: Calculate the percentage left

X = 100 / 2^n

⇒ with X = The amount of sample after 12.6 days

⇒ with n = (time passed / half-life time) = (12.6/14.3)

X = 100 / 2^(12.6/14.3)

X = 54.29

There is 54.29 % sample left after 12.6 days

8 0
3 years ago
A lamp releases only light and thermal energy. The energy input of the lamp is 120 watts. Of that input, 80 watts is converted t
fomenos
40 watts because 120-80 is forty or 80 + 40 - 120
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