2.4368 MILOGRAMS is burned
Answer: 8 moles
Explanation:
C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)
The balanced equation above shows the combustion of propane, C3H8 (for x is 3; y is 8) in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O
The mole ratio on combustion are as follows:
5 moles of O2 react to produce 3 moles of CO2
Z mole of O2 react to produce 4.8 moles of CO2
To get the value of Z, cross multiply
4.8 moles x 5 mole = 3 mole x Z
24 = 3Z
Divide both sides by 3
24/3 = 3Z/3
8 = Z
Thus, in the combustion of propane, 8 moles of oxygen (O2) are needed to react to produce 4.8 moles of carbon dioxide (CO2)
Finish their experiment and conclusions, then remake their observations and reform a new hypothesis and procedure, and repeat until they are correct
<h2>
Hello!</h2>
The answer is:
The correct option is option C.

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Why?</h2>
To calculate the volume of the gas sample, we need to use the Ideal Gas Law, this equation is used to relate the pressure, the volume, the mass and the temperature of a gas, so, we can isolate the volume from it.
The Ideal Gas Law equation is equal to:

Where,
P is the pressure (in atm)
V is the volume (in liter)
n is the mass of the gass (in mole)
T is the temperature of the gass (absolute temperature)
So, from the statement we know that:

Then, substituting and calculating we have:

Now, rounding to the nearest whol number we have that the volume is equal to 36 L.
Hence, the correct option is option C.
Have a nice day!
The answer is A
explanation:
We know that the atomic weight of carbon is 12 grams and that of oxygen is 16 grams. Hence we have calculated the mass 5 of carbon in carbon dioxide to be 27.27%.