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Triss [41]
4 years ago
12

rite stepwise equations for protonation or deprotonation of this polyprotic species in water. What are the products of the first

step? CO32- + H2O → __ + __ CO32- + H2O →
Chemistry
1 answer:
adoni [48]4 years ago
3 0

<u>Answer:</u> The products of the given chemical equation are HCO_3^-\text{ and }OH^-

<u>Explanation:</u>

Protonation equation is defined as the equation in which protons get added in the substance.

The chemical equation for the protonation of carbonate ion in the presence of water follows:

CO_3^{2-}+H_2O\rightarrow HCO_3^-+OH^-

By Stoichiometry of the reaction:

1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion

Hence, the products of the given chemical equation are HCO_3^-\text{ and }OH^-

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What is the relationship between potential energy and speed
WARRIOR [948]

Answer:

For the purposes of your question, we can think of speed and velocity as being the same thing. Therefore, the potential energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the potential energy will increase by a factor of four.

4 0
3 years ago
An aqueous solution containing 17.5 g of an unknown molecular compound in 100.g water was found to have a freezing point of-1.8°
Zigmanuir [339]

Answer:

The answer to your question is 178.6 g

Explanation:

Data

ΔT = 1.8 °C

mass = 17.5 g

mass of water = 100 g

Kc = 1.86

Process

1.- Calculate the molality using the following formula

    ΔTc = mKc

solve for m

    m = ΔTc/Kc

substitution

     m = 1.8/1.86

result

     m = 0.968

2.- Calculate the number of moles

    m = # of moles/kg of solvent

kg of solvent = 0.1 kg

     # of moles = m x kg of solvent

     # of moles = 0.968 x 0.1

     # of moles = 0.0968

3.- Calculate the molar mass

        x g molar mass --------------------- 1 mol

       17.5 g                  --------------------- 0.0968 moles

       x = (1 x 17.5)/0.0968

      x = 178.6 g

             

4 0
3 years ago
the countercurrent arrangement of the two limbs of the loop of henle becomes a multiplier of electrolyte concentration due to wh
enot [183]

The counter-current is the process that occurs in the excretory system. The limbs become the multiplier because of the active transport of the electrolytes that move out.

<h3>What is the loop of Henle?</h3>

The loop of Henle is the part of the excretory system and part of the nephron. It functions in minimizing the water loss in the excretion of urine. There are descending and ascending loops present.

The ascending loop is impermeable to water but permeable to the electrolytes, and hence the concentration of the sodium, potassium, and chloride ions are actively pumped. This makes the solution more concentrated in the ascending loop.

Therefore, the electrolyte concentration results in active transport.

Learn more about the loop of Henle here:

brainly.com/question/13191804

#SPJ4

5 0
2 years ago
This solution contains equal concentrations of both hf(aq) and naf(aq). write the proton transfer equilibrium (net ionic) reacti
Viktor [21]
Net ionic reaction for the solution containing equal concentrations of both HF(aq) and NaF(aq) is as follow:
F⁻(aq) + H₂O(l) ⇄ HF(aq) + OH⁻(aq)
3 0
3 years ago
Read 2 more answers
Find δh°rxn for the reaction ch4(g) + 2o2(g) → co2(g) + 2h2o(l). [δh°f (ch4(g)) = –74.8 kj/mol; δh°f (co2(g)) = –393.5 kj/mol; δ
saveliy_v [14]
398923 is yo answer home slice
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