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den301095 [7]
3 years ago
8

Why do you think the atomic number is basically represented by the number of protons and not the number of electrons?

Chemistry
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

The atomic number equals the charge on the nucleus. It therefore also equals the number of protons in the nucleus and also equals numerically the number of electrons in the neutral atom. i think so, hope this helps you

Explanation:

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Which of these substances would you expect to have the LOWEST melting point?
tresset_1 [31]

Answer:

Explanation:

These different types of solids have different properties that depend on the particles ... C4.3i, Explain why ionic solids have higher melting points than covalent solids. ... of each of the six compounds, predict from the Periodic Table which should be ionic ... Check each of six compounds – NaCl, sugar, KCl, KI, camphor, and.

8 0
3 years ago
g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass.
Lady bird [3.3K]

Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

6 0
3 years ago
A gas vessel is charged with a mixture of pcl3(g) and cl2(g), which is allowed to equilibrate at 450 k. at equilibrium the parti
VikaD [51]
Answer is: Kp = 66,586.
Chemical reaction:  PCl₃(g) + Cl₂(g)  ⇔ PCl₅(g).
Kp - equilibrium constants expressed in terms of partial pressures of gases.
Kp = p(PCl₅) ÷ p(PCl₃) · p(Cl₂). p-partial pressure.
Kp = 1,67 atm ÷ 0,132 atm · 0,190 atm
Kp = 66, 586 1/atm. Favors product.
4 0
3 years ago
How many moles in 3.69 x 10^30 molecules of carbon dioxide?
Sedaia [141]

0.612 \times 10^{7} \text { moles of } \mathrm{CO}_{2} are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}

<u>Explanation:</u>

It is known that each mole of an element is composed of avagadro's number of molecules. So if we need to determine, we need to divide the number of molecules with the avagadro's number.

So,

    1 mol of element =6.02 \times 10^{23} molecules of element

As here 3.69 \times 10^{30} molecules of carbon di oxide is given. So the moles in it will be

   No. of moles of carbon dioxide = \frac{3.69 \times 10^{30}}{6.02 \times 10^{23}}

    No. of moles = 0.612 \times 10^{7} moles of carbon dioxide.

Thus,

0.612 \times 10^{7} of carbon dioxide are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}.

4 0
3 years ago
list the following from greatest to least mass: 1 mol of H2, 2 moles of K, 3 moles of Mg, and 4 moles of He
Leya [2.2K]
H₂ = 2 g/mol

1 x 2 = 2 g of H₂
________________________

K = 39.09 g/mol

2 x 39.09 = 78.18 g of K
________________________________
 
Mg = 24.3 g/mol

3 x 24.3 = 72.9 g of Mg
_________________________________

He = 4 g/mol

4 x 4 = 16 g of He
___________________________________

Order :  K , Mg , He  and H₂


hope this helps!
3 0
3 years ago
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