1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Wittaler [7]
3 years ago
12

Read through the literacy task

Chemistry
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

Atoms are the smallest particle that make up living <u>both</u><u> </u><u>living</u><u> </u><u>and</u><u> </u><u>non</u><u> </u><u>living</u><u> </u> things, they are made up of subatomic particles; protons, neutrons and electrons. Of these the electrons <u>protons</u><u> </u> and neutrons are in the nucleus and the protons <u>e</u><u>l</u><u>e</u><u>c</u><u>t</u><u>r</u><u>o</u><u>n</u><u>s</u><u> </u>orbit around the nucleus. Of the subatomic particles, the electrons have the largest <u>s</u><u>m</u><u>a</u><u>l</u><u>l</u><u>e</u><u>s</u><u>t</u><u> </u>mass and are negatively charged, the neutrons (negative charge) (<u>no charge)</u> and protons (positively charged) both have a relative mass of 1. Atoms contain an equal number of protons and neutrons <u>electrons</u>, so carry no overall charge. An element is a substance made up of only two <u>one</u> type of atom. Elements can be found in the Periodic table of elements, they usually have two numbers next to the chemical symbol, the larger number is generally the atomic <u>mass</u> number, which represents the number of neutrons and the number of protons. The smaller number is the relative atomic mass <u>atomic</u><u> </u><u>number</u> which represents the number of electrons or neutrons <u>protons</u>. In order to calculate the number of neutrons, you minus the atomic number from the relative atomic mass.

You might be interested in
How do the test variables (independent variables) and outcome variables (dependent variables) in an experiment compare? A. The o
SVETLANKA909090 [29]

Answer:

C.

Explanation:

8 0
3 years ago
Read 2 more answers
Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI
melamori03 [73]

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%

5 0
3 years ago
How many grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline?
egoroff_w [7]

Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g

Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,

2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0

Molar mass of octane = 114.23g/mol

Molar mass of Oxygen = 32g/mol

According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25

2 mole of octane needs 25 mole of oxygen

1 mole of octane needs 12.5 moleof oxygen

114.23g of octane needs 400g of oxygen

13g   of octane  needs 45.5g of oxygen

Mass of oxygen needed =45.5g

Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

5 0
2 years ago
General Chemistry fourth edition by McQuarrie, Rock, and Gallogly. University Science Books presented by Macmillan Learning.
Helen [10]

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

  • Q: heat absorbed
  • C: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)
  • ΔT: temperature change (2.29 °C)

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

3 0
3 years ago
1. NaOH mass of a solution of 200g in which its percentage is 25%. What mass of sulfuric acid solution is needed to completely n
Ede4ka [16]

Answer:

m_{H2SO4 = 61.25 g

m_{Na2SO4} = 88.75 g

Explanation:

m_{NaOH} = \frac{200 . 25 }{100} = 50 g

⇒ n_{NaOH} = \frac{50}{40} = 1.25 (moles)

2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O

   2        :     1           :      1         :    2

 1.25                                                       (moles)

⇒  n_{H2SO4} = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒ m_{H2SO4} = 0.625 × 98 = 61.25 g

    n_{Na2SO4} = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒m_{Na2SO4} = 0.625 × 142 = 88.75 g

4 0
3 years ago
Other questions:
  • Jose and Sarah are running in the cross country meet. Their skeletal and muscular systems work to move them through the course.
    7·1 answer
  • What are the products when anaerobic respiration occurs in yeast cells?
    5·2 answers
  • In part a, we saw that the theoretical yield of aluminum oxide is 0.700 mol . calculate the percent yield if the actual yield of
    7·1 answer
  • _________ is caused by deficiency of Vitamin A​
    12·2 answers
  • The formula is used to calculate the yield of a reaction.
    11·2 answers
  • What is the mobile phase in chromatography
    7·1 answer
  • What is the picture for ?
    5·1 answer
  • 1220 pounds / 1.45 inches =?<br> What do you get when you quadruple 22.34 cm?
    10·1 answer
  • The weight for this compound is 74. what is the molecular formula​
    5·1 answer
  • The reaction
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!