Answer:
13.687 grams of salt should be added
The total grams of 8.6% of brine solution produced is 852.687g
Explanation:
Solution mass= 962g
Salt= 6.2%
Water = 93.8%
962 gram of water is made up of:
902.356g ( due to vaporization which reduces mass)
= 902.356 - 123
= 779. 356g of water
59.644g of salt.
If we add x gram of salt for making brine solution up to 8.6%
=(59. 644g + x)g.of salt
% salt = Mass of Salt / Total mass of solution
= 0.086= 59.644 + x / 779.356 + 59.644 + x
= 59.644 + x / 839 + x
x= 13.687 g of salt
Grams of 8.6% brine solution will be:
Gram of water + total gram of salt added to form 8.6% brine solution.
= 779.356g +59.644g + 13.687g
= 852.687g
The total grams of 8.6% of brine solution produced is 852.687g
The Calcium atom has 2 valence electrons but a Calcium ion will have no electrons because it is a cation ion. Meaning that there are more protons than electrons. Also, the normal calcium symbol is Ca but the calcium ion is Ca²⁺
I hope this wasn't too late
Mg- is the isoelectronic of Na
Answer:
The pH value of the mixture will be 7.00
Explanation:
Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,
![pH=pK_{a} + log(\frac{[Base]}{[Acid]})](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%20%2B%20log%28%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%29)
According to the given conditions, the equation will become as follow
![pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})](https://tex.z-dn.net/?f=pH%3DpK_%7Ba%7D%20%2B%20log%28%5Cfrac%7B%5BNa_%7B2%7DHPO_%7B4%7D%20%5D%7D%7B%5BNaH_%7B2%7DPO_%7B4%7D%5D%7D%29)
The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.
Placing all the given data we obtain,

