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o-na [289]
3 years ago
15

Instrument used to measure capacity​

Physics
2 answers:
Andre45 [30]3 years ago
6 0

Answer:

measuring cup

The most popular tool used to measure capacity is the measuring cup.

Anni [7]3 years ago
6 0

Answer:

measuring cup

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A long, rigid conductor, lying along an x axis, carries a current of 4.99 A in the negative x direction. A magnetic field is pre
Tcecarenko [31]

Answer with Explanation:

We are given that

Current in conductor=I=4.99 A  (-x direction)

Magnetic field=B=3.72\hat{i}+8.72x^2\hat{j}mT=(3.72i+8.72x^2j)\times 10^{-3}

(1mT=10^{-3} T)

x(in m) and B (in mT)

Length of conductor is given in negative x- direction

\vec{L}=-x\hat{i}

dL=-dx\hat{i}

Force on current carrying conductor is given by

F=I(L\times B)

dF=I(dL\times B)

Integrating on both sides then we get

\vec{F}=\int_{1.41}^{2.77}(4.99)(-dx\hat{i}\times (3.72\hat{i}+8.72x^2\hat{j}))\times 10^{-3}

\vec{F}=-\int_{1.41}^{2.77}(4.99\times 10^{-3})\cdot 8.72(x^2\hat{k})dx  (i\times i=0, i\times j=k

\vec{F}=-(4.99\times 10^{-3}\times 8.72)[\frac{x^3\hat{k}}{3}]^{2.77}_{1.41}

\vec{F}=-\frac{(4.99\times 10^{-3}\cdot 8.72)}{3}((2.77)^3-(1.41)^3)\hat{k}

\vec{F}=-0.268 \hat{k} N

a. x- component of force=0

b.y- component of force=0

c.z- component of force=-0.268 N

5 0
3 years ago
HURRY What happened when the speed was increased?
sp2606 [1]
What happened to what?
7 0
3 years ago
Read 2 more answers
When your sled starts down from the top of a hill, it hits a frictionless ice slick that extends all the way down the hill. At t
Blababa [14]

Answer:

Explanation:

Given that,

Height of hill is 50m

Coefficient of friction is μ=0.62

Energy is conserved, then

K.E at the bottom of the hill is equally to P.E at the top of the hill

½mv²=mgh

Mass cancel out

½v²=gh

v²=2gh

v=√2gh

Since g=9.81 and h=50

v=√2×9.81 ×50

v=31.32m/s

This is the initial speed at the bottom of the hill

At the bottom of the hill 3 forces are acting on the body

1. Weight,

2. Normal

3. Frictional force

Now taking newton law of motion

ΣF = ma.

Along y axis, since the body is not moving in y direction, they acceleration along y is 0m/s²

ΣFy = 0

N-W=0

N=W

Since weight =mg

N=W=mg

Using law of friction, Fr=μN

Therefore,

Fr=μmg

Applying Newton law to the x-direction

ΣFx = ma

Fr=ma,

Since Fr=μ mg

μ mg=ma

a=μg

Given that μ=0.62 and g=9.81

a=0.62×9.82

a=6.076m/s²

Since we have acceleration, we can use any of the equation of motion to find distance travel

v²=u²-2gS, . this is due that the box is decelerating and it comes to a halt and this show that final velocity v=0m/s

Then,

0²=31.32²-2×9.81 ×S

-31.32² =-2×9.81×S

S=31.32²/(2×9.81)

S=50.05m

The sled will travel a distance of 50.1m once it reach the bottom

5 0
3 years ago
What is the mechanical advantage supplied by a 1000 N object lifted using 250 N of force
Ivenika [448]

Answer:

Mechanical advantage=4

Explanation:

Load=1000N

Effort=250N

mechanical advantage=load/effort

Mechanical advantage=1000/250

Mechanical advantage=4

4 0
4 years ago
An object has a mass of 20 kg. Determine its weight, in N, at a location where the acceleration of gravity is 9.78 m/s2.
pychu [463]

Answer:

Weight of the object will be 195.6 N

Explanation:

We have given mass of the object m = 20 kg

And acceleration due to gravity at any location is given g=9.78m/sec^2

We have to find the weight of the object in N at the location where value of acceleration due to gravity is g=9.78m/sec^2

Weight of the object is given by W = mg , here W is weight , m is mass and g is acceleration due to gravity

So weight W = 20×9.78 = 195.6 N

So weight of the object will be 195.6 N

3 0
3 years ago
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