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Snezhnost [94]
2 years ago
13

Find the L.C.M of 6,12,18​

Mathematics
1 answer:
Rashid [163]2 years ago
3 0
The least common multiple is 36.

6x6= 36
12x3=36
18x2=36
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Please say A,B,C, or D and if you are correct I will mark you brainlest. Thank you :)
mario62 [17]
Pretty sure it’s d hoped I helped
3 0
3 years ago
Which is the area of a square with one side that measures 1 foot
AleksAgata [21]
I think that would be one . A=s*s A=1*1
5 0
2 years ago
Read 2 more answers
In 10 minutes, the top three finishers in a hot dog eating contest consumed a total of 130 hot dogs. the winner, person a, ate 8
Vera_Pavlovna [14]
Let x be how many hot dogs person b ate

therefore, person a ate x+8 hotdogs
and person c ate x-10 hotdogs

they all ate 130 hotdogs in total so
x + x + 8 + x - 10 = 130
3x -2 = 130
3x = 132
x = 44

so person b ate 44 hotdogs
person a ate 8 more so 52 hotdogs
and person c ate 10 less than person b so 34 hotdogs
4 0
2 years ago
Date
Nitella [24]

Answer:

perimeter =22m

area=28square meter

perimeter of rectangle=4l

22m=4l

22÷4=l

5.5=l

l=5.5m

area of rectangle =l×b

28=5.5×b

28÷5.5=b

5.09=b

b=5.09m

length =5.5m and breadth =5.09m answer !!!!

7 0
2 years ago
A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL
LiRa [457]

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

5 0
3 years ago
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