2a for example the first one,2sec. You know that every second it moves 3metres further. So 2x3=6 but you start at 0.50m so 6+0.50=6.5
Answer:
the average force 11226 N
Explanation:
Let's analyze the problem we are asked for the average force, during the crash, we can find this from the impulse-momentum equation, but this equation needs the speeds and times of the crash that we could look for by kinematics.
Let's start looking for the stack speeds, it has a free fall, from rest (Vo=0)
Vf² = Vo² - 2gY
Vf² = 0 - 2 9.8 7.69 = 150.7
Vf = 12.3 m / s
This is the speed that the battery likes when it touches the beam. They also give us the distance it travels before stopping, let's calculate the time
Vf = Vo - g t
0 = Vo - g t
t = Vo / g
t = 12.3 / 9.8
t = 1.26 s
This is the time to stop
Now let's use the equation that relates the impulse to the amount of movement
I = Δp
F t = pf-po
The amount of final movement is zero because the system stops
F = - po / t
F = - mv / t
F = - 1150 12.3 / 1.26
F = -11226 N
This is the average force exerted by the stack on the vean
When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time
During this contact interval we can say they will exert normal force on each other
This normal force is always equal and opposite on two balls which means this force will follow Newton's III law
It will be same in magnitude but opposite in the direction
So here correct answer would be
<u><em>They both experience the same magnitude of the collision force.</em></u>
Answer:
51.94°
Explanation:
= Unpolarized light
= Light after passing though second filter = 
Polarized light passing through first filter
Polarized light passing through second filter
The angle between the two filters is 51.94°
