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MakcuM [25]
3 years ago
14

Consider continuous functions f and g. Then complete the statement.

Mathematics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

I just randomly picked greater than.... hopefully somone will know but who knows maybe thats the right answer

Step-by-step explanation:

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X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

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The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W
Alex_Xolod [135]

Answer:

center = (-2, 6)

radius = 6

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

x^2+y^2+4x-12y+4=0

Collect like terms and subtract 4 from both sides:

\implies x^2+4x+y^2-12y=-4

Complete the square for both variables by adding the square of half of the coefficient of x and y to both sides:

\implies x^2+4x+\left(\dfrac{4}{2}\right)^2+y^2-12y+\left(\dfrac{-12}{2}\right)^2=-4+\left(\dfrac{4}{2}\right)^2+\left(\dfrac{-12}{2}\right)^2

\implies x^2+4x+4+y^2-12y+36=-4+4+36

Factor both variables:

\implies (x+2)^2+(y-6)^2=36

Therefore:

  • center = (-2, 6)
  • radius = √36 = 6
7 0
1 year ago
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