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3 years ago

Four less than the product of 5 and a number is equal to 9 . Use the variable (w) for the unknown number

Mathematics

1 answer:

ivann1987 [24]3 years ago

3 0

Answer:

w = 13/5

Step-by-step explanation:

The equation is : 5w-4=9

Then we add 4 to each side

5w = 13

Then we divide by 5

w = 13/5

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On a baseball

vampirchik [111]

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

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1 year ago

John bought a new home in 2002. The value of the home increases 4% each year. If the price of the house is $375,000 in 2020, how

skad [1K]

Using the formula of P(1 + r)^n = x where p represents the initial value, r represents the rate and n represents the number of years and x is our final output. We want to find P so we have to make it the subject of the equation.

1 + 0.04 = 1.04
1.04^18 = 2.025816515
Then divide the total amount by this to get 185,110.5454
Therefore the answer is $185,110.55

Hope this helps! :)

4 0

2 years ago

Could someone help me and explain?

ExtremeBDS [4]

Answer:

length 3 in
width 2 in

Step-by-step explanation:

Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.

The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...

gardener's drawing = (1/4)actual size

actual size = 4(gardener's drawing)

The partner's drawing is 1/20 of actual size, so is ...

partner's drawing = actual size/20 = (4(gardener's drawing))/20

partner's drawing = (4/20)(gardener's drawing)

partner's drawing = (gardener's drawing)/5

Then the {length, width} of the partner's drawing are ...

partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}

The partner's drawing has a length of 3 inches and a width of 2 inches.

6 0

3 years ago

What values of the variables highlighted would create an equation infinitely many solutions

Otrada [13]

A = -5
b = 2
I’m pretty sure

3 0

2 years ago

Pls help I don't understand:

sineoko [7]

Answer:

Part a) $T(d)=2d+30$

Part b) $T(6)=42\ minutes$

Step-by-step explanation:

Part a) Write an equation for T (d)

Let

d ----> the number of days

T ---> the time in minutes of the treadmill

we know that

The linear equation in slope intercept form is equal to

$T=md+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

The slope or unit rate is

$m=2\ \frac{minutes}{day}$

The y-intercept or initial value is

$b=30\ minutes$

substitute

$T(d)=2d+30$

Part b) Find T (6), the minutes he will spend on the treadmill on day 6

For d=6

substitute in the equation and solve for T

$T(6)=2(6)+30$

$T(6)=42\ minutes$

8 0

2 years ago