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3 years ago

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The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points rad

ially toward the center of the sphere.What is the net charge within the sphere's surface

1 answer:

Igoryamba3 years ago

8 0

Answer:

Q = -52.56 nC

Explanation:

The electric field outside a spherical shell is given by

$E = \frac{k*Q}{r^{2} }$

where:

Q is the net charge

r is the radius of the spherical shell and E is the electric field magnitude.

Given:

r = 0.725 m

since the field points radially toward the center of the sphere, E = -899 N/C.

k is a constant with a value = 8.99 x 109 Nm²/C².

∴ $-899 = \frac{8.99*10^{9} *Q}{0.725^{2} }$

$Q = \frac{-899*0.725^{2} }{8.99*10^{9} }=-5.256*10^{-8}$

Q = -52.56 nC

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