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3 years ago

The maximum current output of a 60 ω circuit is 11 A. What is the root mean square voltage of the circuit?

Physics

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

660V

Explanation:

V=IR

V=?, I=11A,R=60w

V=60 ×11

=660V

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What is the period of a soundwave whose wavelength is 20.0 m? Use values from the book and show ALL of your work.

Liono4ka [1.6K]

<h3>Answer;</h3>

Period = 1/17 seconds

<h3>Explanation;</h3>

Wavelength is related to period by the expression:

speed = wavelength / period 

If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.

Given the speed of sound wave as 340 m/s

Period = Wavelength/ speed

= 20 m/340 m/s

= 1/17 seconds

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3 years ago

Suppose light from a 632.8 nm helium-neon laser shines through a diffraction grating ruled at 520 lines/mm. How many bright line

Leya [2.2K]

Answer:

1 bright fringe every 33 cm.

Explanation:

The formula to calculate the position of the m-th order brigh line (constructive interference) produced by diffraction of light through a diffraction grating is:

$y=\frac{m\lambda D}{d}$

where

m is the order of the maximum

$\lambda$ is the wavelength of the light

D is the distance of the screen

d is the separation between two adjacent slit

Here we have:

$\lambda=632.8 nm = 632.8\cdot 10^{-9} m$ is the wavelength of the light

D = 1 m is the distance of the screen (not given in the problem, so we assume it to be 1 meter)

$n=520 lines/mm$ is the number of lines per mm, so the spacing between two lines is

$d=\frac{1}{n}=\frac{1}{520}=1.92\cdot 10^{-3} mm = 1.92\cdot 10^{-6} m$

Therefore, substituting m = 1, we find:

$y=\frac{(632.8\cdot 10^{-9})(1)}{1.92\cdot 10^{-6}}=0.330 m$

So, on the distant screen, there is 1 bright fringe every 33 cm.

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3 years ago

What are the 4 energy transformations of a dash toy

Hunter-Best [27]

Answer:

Thermal/Heat energy, kinetic energy, light energy, & Electromagnetic energy

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3 years ago

A lamp in a child's Halloween costume flashes based on an RC discharge of a capacitor through its resistance. The effective dura

Genrish500 [490]

Power of the lamp = (voltage) x (current)

0.62 watt = (3.0 v) x (current)

Current = (0.62 watt) / (3.0 volt)

Current = 0.207 Ampere

Charge = (current) x (time)

Charge = (0.207 Amp) x (0.32 sec)

a). Charge = 0.066 Coulomb

Energy discharge through the lamp = (charge) x (voltage)

Energy = (0.66 C) x (3.0 volt)

Energy = 0.1984 Joule

Energy stored in a capacitor = (1/2) (Capacitance) (voltage²)

0.1984 Joule = (1/2) (Cap) (3.0 v)²

Cap = 2 x 0.1984 / 9

b). Cap = 0.044 Farad (yikes !)

Resistance of the lamo = (voltage) / (current)

Resistance = (3.0 volt) / (0.207 Amp)

c). Resistance = 14.49 Ω

All of this feels OK except for that ridiculous 44,000 μF, 3v capacitor. Sadly, I have checked my work without finding an error, and I am too lazy to check it again. So I'll call this my final answer, and leave it to some better Brainly person to find where I went wrong.

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4 years ago

A light-year is a unit of

S_A_V [24]

A light-year is a unit of length or distance.
It's defined as the distance that light (or any electromagnetic
wave) travels through vacuum in one Earth-year.

==> about 9,460,730,000,000,000 meters

==> about 5,878,620,000,000 miles

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3 years ago

Read 2 more answers