<span>To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from the x axis. </span> <span>The 110 N force is said to act at 90 deg which means it is along the Y axis. The </span><span>55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the </span> <span>X component of the resultant force = 55 N </span> <span>Y component of the resultant force = 110 N </span> <span>Magnitude of the resultant force would be calculated as follows: R = √(Fx^2 + Fy^2) R = √(55^2 + 110^2) </span> <span>R = √(15125) </span> <span>R = 123 N </span> <span>The resultant force would have its terminal side in the x-axis. We calculate angle θ as follows: </span> <span>tan θ = Fy/Fx </span> <span>tan θ = 110 N /55 N = 2 </span>θ = arctan(2) θ <span>= 63.4 degrees </span>Therefore, the m<span>agnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.</span>
D = 110 m, t = 5 s v o = 110 cs : 5 m = 22 m/s ------------------------------------- v = v o - a t v = 0 m/s, v o = 22 m/s, t = 4 s 0 = 22 - 4 a 4 a = 22 a = 22 : 4 a = 5.5 m/s² g = 9.80 m/s² 9.80 : 5.5 = 0.56 Answer: The magnitude of its acceleration is 5.5 m/s or 0.56 g.