Answer:
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Well, part of 'velocity' is the direction of the motion, and the graph doesn't give us any information about the direction. So the best we'll be able to do is find the average SPEED of the car.
On a distance/time graph, the speed is just the slope of the line. Since this graph is a straight line, it doesn't matter which points along the line you choose ... the answer will always be the same.
Average speed = (distance covered) / (time to cover the distance)
Let's use the ends of the line ... the origin, and the point at the top.
On the left side of the graph, we see the label 'Distance (m)', and I don't know what 'm' stands for. It could be 'miles' or 'meters'.
Anyway, the point at the top of the line shows that the car covered a distance of 25.0 'm' in 10.0 s of time.
Average speed = (25 m) / (10 s)
Average speed = (25/10) m/s
(I'm pretty sure that 'm' means 'meters' and 's' means 'seconds'.)
1) Displacement: -49 m, in the negative direction
Explanation:
The displacement of an object is a vector, whose magnitude is given by the difference between the final point of the motion and the starting point:
In this problem, the starting point is +34 m, while the final position is -15 m; therefore, the displacement is:
and the direction is negative, in according to the negative sign.
2) Velocity: -3.27 m/s
Explanation:
Velocity is equal to the ratio between the displacement and the time taken:
in this problem, we have:
d = -49 m is the displacement
t = 15 s is the time
therefore, the velocity is
and the direction is negative.
The second law states that the total entropy can never decrese over time for an isolated system