Answer:
7.535×10^25 earth mass
Explanation:
for an approximate result,divide the mass value by 9.223e+18
600Hz is the driving frequency needed to create a standing wave with five equal segments.
To find the answer, we have to know about the fundamental frequency.
<h3>How to find the driving frequency?</h3>
- The following expression can be used to relate the fundamental frequency to the driving frequency;
f(n) = n * f (1)
where, f(1) denotes the fundamental frequency and the driving frequency f(n).
- The standing wave has four equal segments, hence with n=4 and f(n)=4, we may calculate the fundamental frequency.
f(4) = 4× f (1)
480 = 4× f(1)
f(1) = 480/4 =120Hz.
So, 120Hz is the fundamental frequency.
- To determine the driving frequency necessary to create a standing wave with five equally spaced peaks?
- For, n = 5,
f(n) = n 120Hz,
f(5) = 5×120Hz=600Hz.
Consequently, 600Hz is the driving frequency needed to create a standing wave with five equal segments.
Learn more about the fundamental frequency here:
brainly.com/question/2288944
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![\LARGE{ \underline{\underline{ \purple{ \bf{Required \: answer:}}}}}](https://tex.z-dn.net/?f=%20%5CLARGE%7B%20%5Cunderline%7B%5Cunderline%7B%20%5Cpurple%7B%20%5Cbf%7BRequired%20%5C%3A%20answer%3A%7D%7D%7D%7D%7D)
GiveN:
- Initial velocity = 9.8 m/s²
- Accleration due to gravity = -9.8 m/s²
- Time taken = 1 s
To FinD:
- Final velocity of the ball?
Step-by-step Explanation:
Using the first Equation of motion,
⇒ v = u + gt
⇒ v = 9.8 + -9.8(1)
⇒ v = 0 m/s
The final velocity is hence <u>0</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>
<h3>
Note:</h3>
- While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.
- You can consider positive above the ground and negative for towards it.
PART a)
here when stone is dropped there is only gravitational force on it
so its acceleration is only due to gravity
so we will have
![a = g = 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%20g%20%3D%209.8%20m%2Fs%5E2)
Part b)
Now from kinematics equation we will have
![y = v_i t + \frac{1}{2} at^2](https://tex.z-dn.net/?f=y%20%3D%20v_i%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
now we have
y = 25 m
so from above equation
![25 = 0 + \frac{1}{2}(9.8 )t^2](https://tex.z-dn.net/?f=25%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%289.8%20%29t%5E2)
![t = 2.26 s](https://tex.z-dn.net/?f=%20t%20%3D%202.26%20s)
Part c)
If we throw the rock horizontally by speed 20 m/s
then in this case there is no change in the vertical velocity
so it will take same time to reach the water surface as it took initially
So t = 2.26 s
Part D)
Initial speed = 20 m/s
angle of projection = 65 degree
now we have
![v_x = vcos\theta](https://tex.z-dn.net/?f=v_x%20%3D%20vcos%5Ctheta)
![v_x = 20 cos65 = 8.45 m/s](https://tex.z-dn.net/?f=v_x%20%20%3D%2020%20cos65%20%3D%208.45%20m%2Fs)
![v_y = vsin\theta](https://tex.z-dn.net/?f=v_y%20%3D%20vsin%5Ctheta)
![v_y = 20 sin65 = 18.13 m/s](https://tex.z-dn.net/?f=v_y%20%3D%2020%20sin65%20%3D%2018.13%20m%2Fs)
PART E)
when stone will reach to maximum height then we know that its final speed in y direction becomes zero
so here we can use kinematics in Y direction
![v_f - v_y = at](https://tex.z-dn.net/?f=v_f%20-%20v_y%20%3D%20at)
![0 - 18.13 = (-9.8) t](https://tex.z-dn.net/?f=0%20-%2018.13%20%3D%20%28-9.8%29%20t)
![t = 1.85 s](https://tex.z-dn.net/?f=t%20%3D%201.85%20s)
so it will take 1.85 s to reach the top
Answer:0.906 N/m
Explanation:
Given
time period ![T=0.66 s](https://tex.z-dn.net/?f=T%3D0.66%20s)
mass ![m=0.01 kg](https://tex.z-dn.net/?f=m%3D0.01%20kg)
System can be considered as spring mass system
Time Period of spring mass system is given by
![T=2\pi \sqrt{\frac{m}{k}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7Bm%7D%7Bk%7D%7D)
squaring
![k=\frac{4\pi ^2m}{T^2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B4%5Cpi%20%5E2m%7D%7BT%5E2%7D)
![k=\frac{4\times \pi ^2\times 0.01}{0.66^2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B4%5Ctimes%20%5Cpi%20%5E2%5Ctimes%200.01%7D%7B0.66%5E2%7D)
![k=0.906 N/m](https://tex.z-dn.net/?f=k%3D0.906%20N%2Fm)