Aerobic cellular respiration have 3 parts, this is Glycolysis, Pyruvate Oxidation and Krebs cycle.
<h3>How is the aerobic breathing process?</h3>
Aerobic respiration consists of carrying out the process of degradation of organic molecules, reducing them to molecules with practically no releaseable energy. The products of the initial degradation of the organic molecule are combined with oxygen in the air and transformed into carbon dioxide and water.
In this case, Aerobic cellular respiration have 3 parts:
- Glycolysis(yeilds 2ATP & 2NADH).
- Pyruvate Oxidation(yeilds 2NADH).
- Krebs cycle(yeilds 2GTP,2FADH2 & 6NADH).
So the total =4ATPs (2GTP equivalent to 2ATP) +10NADH (equivalent to 30ATPs) + 2FADH2(4 ATPs) =38 ATPs.
See more about Aerobic cellular respiration at brainly.com/question/22531444
#SPJ4
Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy


=37.4mpy
mm/yr


=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Weight of motorcycle on the moon = mg
Here, g= 1.622 m/s²
So, W = 250 * 1.622 = 405.5 Kgm/s² = 405.5 N.
Did you understand??
Answer:
23 mi
Explanation:
Let us first record all the values we have
acceleration = 4 ft/s
max speed = 90 mi/hr * 1 hr/3600s * 5280 ft/1 mi = 132 ft/s
We can use the equation of linear motion since acceleration is constant
distance covered = distance during acceleration + distance during costant
velocity

distance in miles = 120 978 ft * 1 mi/5280 ft = 22.9125 mi ≈ 23 mi