1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VladimirAG [237]
3 years ago
11

A block slides on a table pulled by a string attached to a hanging weight. In case 1 the block slides without friction and in ca

se 2 there is kinetic friction between the sliding block and the table. In which case is the tension in the string the biggest? Please explain.
Physics
2 answers:
ycow [4]3 years ago
7 0

The tension in the string with friction would be the biggest because of the involvement of the force of gravity. This would result in that the friction force that is acting on the system. There is no friction in the frictionless system, and only the force of gravity is relevant.

ankoles [38]3 years ago
7 0

Answer:

In case 2

Explanation:

Thinking process:

The friction is a force that tends to oppose motion.

In case 1, the block slides without friction. This means that the surface is a smooth surface. Thus, the net force needed to pull the string is minimal.

In case 2, there is kinetic friction between the sliding block and the table. Now, the kinetic friction is given by the formula:

F = \muN\mu N

where, \mu = coefficient of friction and N = normal force.

Thus, the net force needed:

F_{net} = F_{pull} - \mu N

Thus, the force is larger in case 2.

Therefore, the tension is larger in case 2.

You might be interested in
Describe the steps of aerobic cellular respiration and the amount of energy produced by each step.
Setler [38]

Aerobic cellular respiration have 3 parts, this is Glycolysis, Pyruvate Oxidation and Krebs cycle.

<h3>How is the aerobic breathing process?</h3>

Aerobic respiration consists of carrying out the process of degradation of organic molecules, reducing them to molecules with practically no releaseable energy. The products of the initial degradation of the organic molecule are combined with oxygen in the air and transformed into carbon dioxide and water.

In this case, Aerobic cellular respiration have 3 parts:

  • Glycolysis(yeilds 2ATP & 2NADH).
  • Pyruvate Oxidation(yeilds 2NADH).
  • Krebs cycle(yeilds 2GTP,2FADH2 & 6NADH).

So the total =4ATPs (2GTP equivalent to 2ATP) +10NADH (equivalent to 30ATPs) + 2FADH2(4 ATPs) =38 ATPs.

See more about Aerobic cellular respiration at brainly.com/question/22531444

#SPJ4

3 0
2 years ago
A thick steel sheet of area 100 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig
vladimir1956 [14]

Answer:

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

Explanation:

The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

CPR=\frac{KW}{DAT}

K= constant depends on the system of units used.

W= weight =485 g

D= density =7.9 g/cm³

A = exposed specimen area =100 in² =6.452 cm²

K=534 to give CPR in mpy

K=87.6  to give CPR in mm/yr

mpy

CPR=\frac{KW}{DAT}

        =\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}

        =37.4mpy

mm/yr

CPR=\frac{KW}{DAT}

        =\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}

       =0.952 mm/yr

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

3 0
4 years ago
The mass of your new motorcycle is 250kg. What is the weight on the moon in newtons
Hunter-Best [27]

Weight of motorcycle on the moon = mg

Here, g= 1.622 m/s²

So, W = 250 * 1.622 = 405.5 Kgm/s² = 405.5 N.

Did you understand??


8 0
3 years ago
A high-speed ""bullet"" train accelerates and decelerates at the rate 4 ft/s 2 . Its maximum cruising speed is 90 mi/hr. (a) Wha
NemiM [27]

Answer:

23 mi

Explanation:

Let us first record all the values we have

acceleration = 4 ft/s

max speed = 90 mi/hr * 1 hr/3600s * 5280 ft/1 mi = 132 ft/s

We can use the equation of linear motion since acceleration is constant

distance covered = distance during acceleration + distance during costant

                                 velocity

s = \frac{v_{f} ^{2} - v_{i} ^{2}  }{2a}  + v_{i}t\\\\s = \frac{132 ^{2} - 0^{2}  }{2*4}  + 132*900\\s = 120 978ft

distance in miles = 120 978 ft * 1 mi/5280 ft = 22.9125 mi ≈ 23 mi

4 0
3 years ago
Anyone want text if yes ill give u my phone number
Jlenok [28]

Answer:

Explanation:OFC!!!

3 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following accurately describes semiconductor diodes?
    15·2 answers
  • When did dalton form his atomic theory?
    14·2 answers
  • A chemist notices some silvery liquid on the floor in her lab. She wonders if someone accidentally broke a mercury thermometer,
    10·1 answer
  • What does WNBA stand for
    10·2 answers
  • How long will it take an object to hit the ground if dropped from 100 meters
    11·2 answers
  • A ray moving in air at 62.9 deg
    11·1 answer
  • What reasoning is empirical in nature
    14·2 answers
  • I will mark brainliest
    7·1 answer
  • A biker with an initial velocity of 16.0 m/s slows uniformly to 6.0 m/s in 8.0 seconds. What is the acceleration of the car duri
    7·1 answer
  • People's perceptions of what is important in life are known as:
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!