Answer:
1456 N
Explanation:
Given that
Frequency of the piano, f = 27.5 Hz
Entire length of the string, l = 2 m
Mass of the piano, m = 400 g
Length of the vibrating section of the string, L = 1.9 m
Tension needed, T = ?
The formula for the tension is represented as
T = 4mL²f²/ l, where
T = tension
m = mass
L = length of vibrating part
F = frequency
l = length of the whole part
If we substitute and apply the values we have Fri. The question, we would have
T = (4 * 0.4 * 1.9² * 27.5²) / 2
T = 4368.1 / 2
T = 1456 N
Thus, we could conclude that the tension needed to tune the string properly is 1456 N
Answer:
W = 100000 J = 100 KJ
Explanation:
Here we will use the most basic and general formula of work, which is as follows:
where,
W = Work Done = ?
F = Force Required = 200 N
d = Length of Track = 500 m
Therefore,
<u>W = 100000 J = 100 KJ</u>
When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.
<h3>Newton's law of universal gravitation</h3>
Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.
The mathematical interpretation of the above law is
Removing the proportionality sign,
Where:
- F = Force of attraction
- G = Gravitational constant
- M = Bigger mass
- m = Smaller mass
- r = Distance between the masses.
From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.
Learn more about Newton's law of universal gravitation here: brainly.com/question/9373839
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The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.
<h3>What is velocity?</h3>
Velocity can be defined as the ratio of the displacement and time of a body.
To calculate the final velocity of Skater 1 we use the formula below.
Formula:
- mu+MU = mv+MV............ Equation 1
Where:
- m = mass of the first skater
- M = mass of the second skater
- u = initial velocity of the first skater
- U = initial velocity of the second skater
- v = final velocity of the first skater
- V = final velocity of the second skater.
make v the subject of the equation.
- v = (mu+MU-MV)/m................ Equation 2
Note: Let left direction represent negative and right direction represent positive.
From the question,
Given:
- m = 105 kg
- u = -2 m/s
- M = 71 kg
- U = 5 m/s
- V = -3.4 m/s.
Substitute these values into equation 2
- v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
- v = (-210+355+241.4)/105
- v = 386.4/105
- v = 3.68 m/s
- v ≈ 3.7 m/s
Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.
Learn more about velocity here: brainly.com/question/25749514
