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svp [43]
3 years ago
6

A ball is thrown upward at a 45° angle. Inthe absence of air resistance, the ballfollows aA. tangential curve.B. sine curve.C. p

arabolic curve.D. linear curve.
Physics
1 answer:
Evgesh-ka [11]3 years ago
8 0

As ball is projected up in air at an angle of 45 degree without any air resistance

Let the initial speed will be v

now we will have

In x direction

v_x = v cos45

in y direction

v_y = vsin45

now displacement in x direction

x = (vcos45)t + 0

displacement in y direction

y = (vsin45)t - \frac{1}{2}gt^2

now from above two equations we have

y = (vsin45)\frac{x}{vcos45} - \frac{1}{2}g(\frac{x}{vcos45})^2

y = xtan45 - \frac{1}{2v^2cos^245}gx^2

so above equation is a quadratic equation and hence it will be a parabolic curve

so correct answer will be

<em>C. parabolic curve.</em>

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Question 1
mestny [16]

Answer:

false

A hypothesis states a presumed relationship between two variables in a way that can be tested with empirical data. ... The cause is called the independent variable; and the effect is called the dependent variable.

6 0
3 years ago
A guitar string is 90 cm long and has a mass of 3.5g . The distance from the bridge to the support post is L=62cm, and the strin
nataly862011 [7]

Answer:

v_1 =  301 Hz

v_2 =  601 \ \ Hz

v_3 =  901 \ Hz

Explanation:

From the question we are told that

     The  length of the string is  l = 90 \ cm  =  0.9 \ m

     The mass of the string is  m_s  =  3.5 \ g =0.0035 \ kg

     The  distance  from the bridge to the support post L =  62 \ c m  =  0.62 \ m

    The tension is T  =  540 \ N

Generally the frequency is mathematically represented as

        v  =  \frac{n}{2 * L }  [\sqrt{ \frac{T}{\mu} } ]

Where n is and integer that defines that overtones

i.e  n =   1 is for fundamental frequency

      n =  2   first overtone

       n =3   second overtone

Also  \mu is the linear density of the string which is mathematically represented as

           \mu  =  \frac{m_s}{l}

=>        \mu  =  \frac{0.0035 }{ 0.9 }

=>       \mu  =  0.003889 \  kg/m

So for   n = 1

     v_1  =  \frac{1}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_1  = 301 \ Hz

So for  n =  2

     v_2  =  \frac{2}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v_2  = 601 \ Hz

So for  n =  3

     v_3  =  \frac{3}{2 *  0.62 }  [\sqrt{ \frac{ 540}{0.003889} } ]

     v  =901  \ Hz

     

       

5 0
4 years ago
How far will a runner travel at an average speed of 5m/s for 20 minutes?
Sonja [21]
Multiply the speed and time to get your answer of how far the runner travels
6 0
3 years ago
A stone is dropped into water from a bridge 52 m above the water's
dusya [7]

Answer:

Its final velocity and how much time it takes to reach the water

Explanation:

The motion of the stone is a uniformly accelerated motion, so we can use the following suvat equation to determine its final velocity:

v^2-u^2=2as

where

v is the final velocity

u = 0 is the initial velocity

a=g=9.8 m/s^2 is the acceleration of gravity

s = 52 m is the distance covered during the fall

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0^2+2(9.8)(52)}=31.9 m/s

We can also find how much time it takes to reach the water, using the equation

v=u+at

where

v = 31.9 m/s is the final velocity

u = 0 is the initial velocity

a=g=9.8 m/s^2

t is the time

And solving for t,

t=\frac{v-u}{a}=\frac{31.9-0}{9.8}=3.26 s

3 0
3 years ago
Which of the following situations correctly describes power? Bill pushed a car for 5 minutes for 20-km while doing 15 J of work.
xxMikexx [17]
I'm warning you before i answer this i'm not guaranteeing i'm going to answer this wright but I'm pretty sure its bill pushed a car for 5 minutes for 20-km while doing 15 J of work. Why I think this is the answer is because it directly tells you the most information giving you the time it took him to move the object that distance and also telling you how many joule's of force he's exerting (power).
Hope this helped :)
6 0
4 years ago
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