Answer:
20 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that the net force applied on an object is equal to the product between the mass of the object and its acceleration:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where
F is the net force
m is the mass
a is the acceleration
In this problem, we have:
m = 10 kg is the mass of the cart
is the acceleration
So the net force on the car is
![F=(10)(2)=20 N](https://tex.z-dn.net/?f=F%3D%2810%29%282%29%3D20%20N)
Since Lucia and Akbar are pushing into opposite directions, this means that this net force is the resultant of the two forces: and since the cart is accelerating towards Akbar, this means that Lucia is applying a force 20 N stronger than Akbar.
D,f,g,h,i,a,e,c,j. I’m sure that it
I am not sure, but i believe it is the distance from the viewing.
Answer:
5.4 m
Explanation:
mass, m = 34 kg
initial velocity, u = 9 m/s
final velocity, v = 0 m/s
coefficient of friction, μ = 0.6
Angle of inclination, θ = 10°
Let teh distance traveled before to come into rest is d.
According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the block.
Work done by the gravitational force = W1 = - mg Sinθ x d
Work done by the frictional force = W2 = - μ N = - μ mg Cosθ x d
negative sign shows that the direction of force and the direction of displacement is opposite to each other.
Total work done W = W1 + w2
W = - 34 x 9.8 x Sin 10 x d - 0.6 x 34 x 9.8 x cos 10 x d
W = - 254.86 d
Change in kinetic energy = 0.5 x m (v^2 - u^2)
= 0.5 x 34 (0 - 81) = - 1377
So, W = change in KE
- 254.86 d = - 1377
d = 5.4 m