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Softa [21]
2 years ago
15

1:

Mathematics
1 answer:
myrzilka [38]2 years ago
5 0
<h2>1:</h2>
  • 100 ounces = 6.25 pints
  • A mile unit is equal to 1760 yards.                                                      inches =mile  * 63360                                                                                              2*63360=126720

       2 Miles = 126720 Inches

  • There are 36 inches in a yard

       3600/36= 100

       3600 inches = 100 yards

  • 1 m = 1/1000 km

       6800/1000 = 6.8

       6800 m = 6.8 km

  • 1 m = 100 cm

        15000/100=150

         15000 cm=150 m

2:

a) Johnson ran  yard in second= 9

     1 minute = 60 second

    Johnson ran yard in one minute=  9 *60= 540 yards

b) Johnson ran  yard in second= 9

     1 hour = 60 minutes *60 second= 1200 seconds

    Johnson ran yard in one hour=  9 *1200= 10,800 yards

c) Johnson ran yard in one hour=  9 *1200= 10,800 yards

   1 mile = 1760 yards

   miles did he run in one hour= 10,800 / 1760 =6

   Johnson ran 6 mile in one hour

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13x=-21-6y and -8x=36+6y
IgorLugansk [536]

Answer:

x=3\\y=-10

Step-by-step explanation:

13x=-21-6y\\-8x=36+6y

Let's take one of the equations and solve for x. I'll take the first one.

13x=-21-6y

Divide by 13.

x=\frac{-21-6y}{13}

Now replace x in the second equation.

-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y

Distribute -8

\frac{168+48y}{13}=36+6y

Break down the fraction.

\frac{168}{13}+\frac{48}{13}y=36+6y

Subtract \frac{168}{13}

\frac{48}{13}y=36+6y-\frac{168}{13}

Subtract 6y

\frac{48}{13}y-6y=36-\frac{168}{13}

Combine like terms;

\frac{48-13*6}{13}y=\frac{36*13-168}{13}

Solve;

\frac{48-78}{13}y=\frac{468-168}{13}

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\frac{-30}{13}y=\frac{300}{13}

Multiply by the negative reciprocal of the fraction next to y.

(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )

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y=-10

After having found y, replace it in any of the equations to find x.

13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3

6 0
3 years ago
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OLEGan [10]

Answer:

PQ = 3.58, and RQ = 10.4

Step-by-step explanation:

We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.  

Hypotenuse = 11,

Opposite side is PQ

Adjacent side is RQ

x = 19

Sin x  = (opposite side)/(hypotenuse)

Cos x = (adjacent side)/(hypotenuse)

For PQ, this is the side opposite to the angle, so use sin,

Sin 19 = x/11

   11(Sin 19) = x

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For RQ, this is the side adjacent to the angle, so use cos,

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   11(Cos 19) = x

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Answer:

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To make that a perfect square polynomial,
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