Mickey walks Pluto 4 miles North to the dog park. Mickey finds beautiful

You are on a cruise ship traveling north at a speed of 13 m/s with respect to land. 1) if you walk north toward the front of the

Brrunno [24]

In order to find the our own velocity with respect to land,we need to apply the theory of relative velocity.

Now consider the velocity of the ship traveling towards the north with respect to land as A.Consider our own velocity headed northwards as B.

The relative velocity is the velocity that the body A would appear to an observer on the body B and vice versa.

In this case the relative velocity would be arrived by summing up our velocity with the velocity of the ship as the object (I) is travelling in the ship.

Relative velocity = Velocity of Body A+ Velocity of Body B.

Velocity of the ship traveling towards the north with respect to land(A)= 13.0m/s. (Given)

Our own velocity headed northwards(B)= 2.8 m/s.

Relative velocity = Velocity of Body A+ Velocity of Body B.

Relative velocity= 13.0 + 2.8 = 15.8m/s.

Thus our own velocity with respect to the land is 15.8 m/s.

5 0

3 years ago

The speed of light in vacuum is defined to be c = 299,792,458 m/s = 1 μ0ε0 . The permeability constant of vacuum is defined to b

Radda [10]

Explanation:

It is given that,

The speed of light in vacuum is, c = 299,792,458 m/s

The permeability constant of vacuum is, $\mu_o=4\pi\times 10^{-7}\ N.s^2/C^2$

Let $\epsilon_o$ is the permittivity of free space. The relation between $\mu_o,\epsilon_o\ and\ c$ is given by :

$c=\dfrac{1}{\sqrt{\mu_o\epsilon_o}}$

$\epsilon_o=\dfrac{1}{c^2u_o}$

$\epsilon_o=\dfrac{1}{(299792458\ m/s)^2\times 4\pi\times 10^{-7}\ N.s^2/C^2}$

$\epsilon_o=8.85\times 10^{-12}\ C^2/N.m^2$

Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

_______ is a vector quantity; ________ is a scalar quantity.

jasenka [17]

Answer: Velocity...Distance

Explanation: Velocity is a vector quantity as it has both magnitude and direction

Distance is a scalar quantity as it has only magnitude and no direction

hope this helped...

7 0

3 years ago

A block of mass 9.2kg rests on a slope an angle of 26.9∘ relative to the horizontal. What is the size of the contact force norma

Olegator [25]

Answer:

80.4 N

Explanation:

As the block is at rest on the slope, it means that all the forces acting on it are balanced.

We are only interested in the forces that act on the block along the direction perpendicular to the slope. Along this direction, we have two forces acting on the block:

- The normal reaction N (contact force), upward

- The component of the weight of the block, $mg cos \theta$ , downward, where m is the mass of the block, g is the gravitational acceleration and $\theta$ is the angle of the incline