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Likurg_2 [28]
3 years ago
8

The author s feeling about a subject or topic, which is evidenced in word choice, is called __________. conflict resolution tone

tension
Physics
2 answers:
Stels [109]3 years ago
6 0
The author s feeling about a subject or topic, which is evidenced in word choice, is called tone.
xeze [42]3 years ago
3 0
<h3><u>Answer;</u></h3>

Tone

The author s feeling about a subject or topic, which is evidenced in word choice, is called <u>tone</u>.

<h3><u>Explanation</u>;</h3>
  • <em><u>Tone indicates or describes the attitude of the author towards a given subject or topic. </u></em>The author's attitude is expressed through the choice of words he or she uses.
  • <u><em>The tone is described by adjectives such as ironic, cynical, intense, sarcastic etc. It may be expressed by use of syntax, point of view, diction, etc. </em></u>
  • <u><em>The tone may change very quickly or may remain the same throughout a topic or a story.</em></u>
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Answer:177.87

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A 0.0250-kg bullet is accelerated from rest to a speed of 550 m/s in a 3.00-kg rifle. The pain of the rifle’s kick is much worse
kondaur [170]

Answer:

a) 4.583 m/s

b) 31.505 J

c) 0.491 m/s

d) 3.375 J

e)

   p_player = (110 kg)(8 m/s) = 880 kg m/s

   p_ball = (0.41 kg)(25 m/s) = 10.25 kg m/s

Explanation:

HI!

a)

We can calculate the recoil velocity by conservation of momentum, remember that p=mv.

The momentum of the bullet is:

p_b = (0.0250 kg)*(550 m/s )

The momentum of the rifle is:

p_r = (3 kg) * v

Since the total initial momentum is zero:

p_b = p_r

That is:

v = (550 m/s ) (0.0250 kg/ 3 kg ) = 4.583 m/s

b)

The kinetic energy gained by the rifle is:

K = (1/2) m v^2 = (1/2) *(3 kg) *(4.583 m/s)^2 = 31.505 J

c)

We use the same formula as in a), but with m=28kg instead of 3 kg

v = (550 m/s ) (0.0250 kg/ 28 kg ) = 0.491 m/s

d)

Again, the same formula as b, but with m=28 and v=0.491 m/s

K = 3.375 J

e)

p_player = (110 kg)(8 m/s) = 880 kg m/s

p_ball = (0.41 kg)(25 m/s) = 10.25 kg m/s

I believe that the kinetic energy is more related to the problem than the momentum. The relation between these two quantities is:

K = p^2/(2m)

usiing this relation, we get:

K_player = 3520 J

K_ball =  128.125 J

Therefore the kinetic energy of the player is around 27 time larger than the kinetic energy of the ball, that being said, the pain of being tackled by that player is around 27 times greater that being hit by the ball!

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mariarad [96]

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