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Likurg_2 [28]
3 years ago
8

The author s feeling about a subject or topic, which is evidenced in word choice, is called __________. conflict resolution tone

tension
Physics
2 answers:
Stels [109]3 years ago
6 0
The author s feeling about a subject or topic, which is evidenced in word choice, is called tone.
xeze [42]3 years ago
3 0
<h3><u>Answer;</u></h3>

Tone

The author s feeling about a subject or topic, which is evidenced in word choice, is called <u>tone</u>.

<h3><u>Explanation</u>;</h3>
  • <em><u>Tone indicates or describes the attitude of the author towards a given subject or topic. </u></em>The author's attitude is expressed through the choice of words he or she uses.
  • <u><em>The tone is described by adjectives such as ironic, cynical, intense, sarcastic etc. It may be expressed by use of syntax, point of view, diction, etc. </em></u>
  • <u><em>The tone may change very quickly or may remain the same throughout a topic or a story.</em></u>
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Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.
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Which is an example of a scientist using a conceptual model to describe a volcano?
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I would say D would be the answer. but is this even a real like homework question 

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4 years ago
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A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
GREYUIT [131]

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

8 0
3 years ago
The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u
irinina [24]

Explanation :

The forces acting on hot- air balloon are:

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Force due to air resistance, (F)

Upthrust force, (U)

Its weight W is acting in downward direction. The upthrust force U acts in upward direction. When the balloon is moving upward, the air resistance is in downward and vice versa.

In this case, the hot-air balloon descends vertically at constant speed.

so, a=0

and F=ma=0

so, W = F + U ....................(1)

when it is ascending let the weight that it is releasing is R, so

(W-R) + F = U..........(2)

solving equation (1) and (2)

(W-R)+F=W-F

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7 0
3 years ago
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A burglar attempts to drag a 108 kg metal safe across a polished wood floor Assume that the coefficient of static friction is 0.
V125BC [204]

Answer:

2.00 m/s²

Explanation:

Given

The Mass of the metal safe, M = 108kg

Pushing force applied by the burglar,  F = 534 N

Co-efficient of kinetic friction, \mu_k = 0.3

Now,

The force against the kinetic friction is given as:

f = \mu_k N = u_k Mg

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N = Normal reaction

g= acceleration due to the gravity

Substituting the values in the above equation, we get

f = 0.3\times108\times9.8

or

f = 317.52N

Now, the net force on to the metal safe is

F_{Net}= F-f

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or

F_{Net}= 216.48

also,

 

F_{Net}= M\timesacceleration of the safe

Therefore, the acceleration of the metal safe will be

acceleration of the safe=\frac{F_{Net}}{M}

or

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or

 

acceleration of the safe=2.00 m/s^2

Hence, the acceleration of the metal safe will be  2.00 m/s²

3 0
3 years ago
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