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Vinil7 [7]
3 years ago
10

Can someone help me with this

Physics
1 answer:
yKpoI14uk [10]3 years ago
4 0

bonded pairs of electrons, lone pairs of electrons.

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Ostrovityanka [42]

Answer:

I wish I knew

Explanation:

5 0
3 years ago
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A reaction has a rate constant of 0.0117 s-1 at 400.0 k and 0.689 s-1 at 450.0 k. calculate the activation energy in kilojoules
Zina [86]
By definition we have to:
 LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
 Where,
 k1 = 0.0117 s-1
 K2 = 0.689 s-1
 T1 = 400.0 k
 T2 = 450.0 k
 R is the ideal gas constant
 R = 8.314 KJ / (Kmol * K)
 Substituting
 ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
 Clearing Ea:
 Ea = 122 kJ
 answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
<span>
</span>
7 0
3 years ago
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6. Convert -180° to radians
icang [17]

Answer:

-3.141593

Explanation:

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4 years ago
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What relates the net force exerted on an object to its mass and acceleration?
insens350 [35]

Answer:

85

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3 years ago
Suppose you find yourself in your friend's third floor apartment building when you smell smoke coming from outside the door. you
Alborosie

(a) Because the tension in the rope would be larger than the maximum value allowed

When you are sliding down the slope, there are two forces acting on you:

- Your weight, W=mg, acting downward, where

m = 70 kg is your mass

g = 9.8 m/s^2 is the acceleration of gravity

- The tension in the rope, T, acting upward

Therefore, the equation of motion is

T-mg=ma

where a is the acceleration.

If you want to slide at constant speed, then the acceleration must be zero:

a = 0

And so the equation becomes

T-mg=0

This means that the tension in the rope must be:

T=mg=(70 kg)(9.8 m/s^2)=686 N

Which is larger than the maximum tension allowed in the rope (500 N), so the rope will break.

(b) 2.66 m/s^2 downward

Again, we must refer to the equation of the forces:

T-mg=ma

In this case, we want the tension in the rope to be the maximum allowed value,

T = 500 N

the other data are

m = 70 kg is your mass

g = 9.8 m/s^2 is the acceleration of gravity

Substituting into the equation, we can find the corresponding value of acceleration:

a=\frac{T-mg}{m}=\frac{500-(70)(9.8)}{70}=-2.66 m/s^2

where the negative sign means the acceleration is downward.

8 0
4 years ago
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