Complete question
A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.
Answer:
The car must travel 68.94 meters.
Explanation:
First, we are going to find the acceleration of the car using Newton's second Law:
(1)
with m the mass , a the acceleration and 
the net force forces that is:
(2)
with F the force provided by traction and f the resistive force:
(2) on (1):
solving for a:
Now let's use the Galileo’s kinematic equation
(3)
With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and 
the time took to achieve that velocity, solving (3) for :
Every piece of matter begins “Out of this world”
If an object has acceleration of zero meters per second², then the object is traveling at a constant speed.
Note: The constant speed doesn't have to be zero, so the object is not necessarily at rest. It can be moving at any speed, as long as the speed doesn't change. (If the speed changed, then the acceleration wouldn't be zero.)
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Answer:
O is an element and H2O2 is a compound.
Explanation:
O is a single element while H2O2 has 2 elements, which makes it a compound.
