D. Light from the sun is reflected off the moon's surface
Negative
Because the car is moving up and the bug is moving down. but it also depends on the weather so choice between one of those two I think is Negative but I may be wrong.
The final velocity of the two pucks is -5 m/s
Explanation:
We can solve the problem by using the law of conservation of momentum.
In fact, in absence of external force, the total momentum of the two pucks before and after the collision must be conserved - so we can write:
![m_1 u_1 + m_2 u_2 = (m_1 +m_2)v](https://tex.z-dn.net/?f=m_1%20u_1%20%2B%20m_2%20u_2%20%3D%20%28m_1%20%2Bm_2%29v)
where
is the mass of each puck
is the initial velocity of the 1st puck
is the initial velocity of the 2nd puck
v is the final velocity of the two pucks sticking together
Re-arranging the equation and solving for v, we find:
![mu_1 + mu_2 = (m+m)v\\u_1 + u_2 = 2v\\v=\frac{u_1+u_2}{2}=\frac{10-20}{2}=-5 m/s](https://tex.z-dn.net/?f=mu_1%20%2B%20mu_2%20%3D%20%28m%2Bm%29v%5C%5Cu_1%20%2B%20u_2%20%3D%202v%5C%5Cv%3D%5Cfrac%7Bu_1%2Bu_2%7D%7B2%7D%3D%5Cfrac%7B10-20%7D%7B2%7D%3D-5%20m%2Fs)
Learn more about momentum:
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The answer is A: can change
The distance between slit and the screen is 1.214m.
To find the answer, we have to know about the width of the central maximum.
<h3>How to find the distance between slit and the screen?</h3>
- It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
- We have the expression for slit width w as,
![w=\frac{2*wavelength*d}{a}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B2%2Awavelength%2Ad%7D%7Ba%7D)
where, d is the distance between slit and the screen, and a is the slit width.
- Thus, distance between slit and the screen is,
![d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m](https://tex.z-dn.net/?f=d%3D%5Cfrac%7Bw%2Aa%7D%7B2%2Awavelength%7D%20%3D%5Cfrac%7B8%2A10%5E%7B-3%7D%2A0.17%2A10%5E%7B-3%7D%7D%7B560%2A10%5E%7B-9%7D%2A2%7D%20%5C%5C%5C%5Cd%3D1.214m)
Thus, we can conclude that, the distance between slit and the screen is 1.214m.
Learn more about the width of the central maximum here:
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