three eggs, each with a mass of ten grams are cooked to make scrambled eggs, what is the total mass of the scrambled eggs

if pete (mass =90.00kg) weighs himself and finds that he weighs 30.0 pounds, how far away from the earth is he?

Svet_ta [14]

Here we know that mass of the person is 90 kg

His weight is given as 30 lbf

so here we can convert it into Newton as we know that

1 lbf = 4.45 N

Now from above conversion

$30 lbf = 30 \times 4.45 = 133.45 N$

now we can use this to find the gravity at this height

$mg = 133.45$

$90\times g = 133.45$

$g = 1.49 m/s^2$

now we know that with height gravity varies as

$g' = g(\frac{R}{R+H})^2$

$1.49 = 9.8(\frac{6.37\times 10^6}{6.37\times 10^6 + h})^2$

$h = 1.0 \times 10^7 m$

so above is the height from the surface of earth

4 0

2 years ago

Quito, Ecuador has an average altitude of 9,350 ft. On a standard day, pressure gage A in a laboratory experiment reads 63 kPa a

kolezko [41]

Explanation:

Below is an attachment containing the solution.

8 0

3 years ago

A glider with a mass of 2 kg is moving rightward at 1 m/s. A second glider, with a mass of 3 kg, is also moving rightward, at 5

Sophie [7]

The velocity of the second glider after the collision is 4.33 m/s rightward.

<h3>Velocity of the second glider after the collision</h3>

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

m₁ is mass of first glider
m₂ is mass of second glider
u₁ is initial velocity of first glider
u₂ is initial velocity of second glider
v is the final velocity of the gliders

(2)(1) + (3)(5) = (2)(2) + 3v₂

17 = 4 + 3v₂

3v₂ = 17 - 4

3v₂ = 13

v₂ = 13/3

v₂ = 4.33 m/s

Thus, the velocity of the second glider after the collision is 4.33 m/s rightward.

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

7 0

1 year ago

A 0.350-m-long cylindrical capacitor consists of a solid conducting core with a radius of 1.20 mm and an outer hollow conducting

Brut [27]

Answer: a. 6.52*EXP{-10}C/m. b. 2.28*EXP{-10}C. c. 38picoFarad.

d. 6.84*EXP{-10}joules

Explanation: We first calculate for the capacitance first. For a concetric cylinder with two radius R1 and R2 the capacitance C is given as

C= {2*pi*permitivity of

freespace*lenght}/In(R2/R1) from the given Question R2 is 2mm and R1 is 1.2mm, lenght is 0.35meter, permitivity of free space is 8.85*EXP {-12} and pi is 3.142.

Therefore Capacitance would be,

C = 2*3.142*8.85*EXP

{-12}*0.35/In(2/1.2)

C = 3.8*EXP {-11} Farad which is also

38*EXP {-12} Farad or 38picoFarad.

Next, we solve for our total charge Q. Charge, capacitance and voltage are related by

Q = C*V = 38*EXP {-12}*6

=2.28*EXP {-10} Coulombs

Next, we obtian charge per unit lenght, which is

Q/L = 2.28*EXP {-10}/0.35

= 6.52*EXP {-10} Coulombs/meter

Next, we obtain the energy stored in the capacitor from

Energy stored = 1/2*(C*V²)

=1/2*38*EXP {-12}*6²

=6.84*EXP {-10} Joules

Note: EXP means 10^

4 0

3 years ago

Read 2 more answers

A person is in a room whose ceiling and two adjacent walls are mirrors. How many images are formed? (A) 5 (B) 6 (C) 7 (D) 8

xz_007 [3.2K]

~Hello there! ^_^

Your question: A person is in a room whose ceiling and two adjacent walls are mirrors. How many images are formed?

Your answer: A person is in a room whose ceiling and two adjacent walls are mirrors.7 images are formed.

The answer is option C.

Hope this helps~

7 0

3 years ago

Read 2 more answers

three eggs, each with a mass of ten grams are cooked to make scrambled eggs, what is the total mass of the scrambled eggs​

three eggs, each with a mass of ten grams are cooked to make scrambled eggs, what is the total mass of the scrambled eggs