Question

Light of wavelength 617 nm passes through a slit 6.30 × 10-6 m wide and falls on a screen that is 2.83 m away. What is the distance on the screen from the center of the central bright fringe to the thrid dark fringe on either side?

Answer 1

Answer:

The distance on the screen from the center of the central bright fringe to the third dark fringe is 0.831 m.

Explanation:

Given that,

Wavelength = 617 nm

Width of slit $d= 6.30\times10^{-6}\ m$

Distance between the slit and screen L= 2.83 m

Third dark fringe m = 3

We need to calculate the distance on the screen from the center of the central bright fringe to the third dark fringe on either side

Using formula of distance

$d \sin\theta=m\lambda$

$\sin\theta=\dfrac{y}{l}$

Put the value into the formula

$d\times\dfrac{y}{L}=m\times\lambda$

$y=\dfrac{m\times\lambda\timesL}{d}$

$y=\dfrac{3\times617\times10^{-9}\times2.83}{6.30\times10^{-6}}$

$y=0.831\ m$

Hence, The distance on the screen from the center of the central bright fringe to the third dark fringe is 0.831 m.