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Zigmanuir [339]
3 years ago
15

A small 22 kilogram canoe is floating downriver at a speed of 2 m/s. What is the canoe's kinetic energy

Physics
2 answers:
VladimirAG [237]3 years ago
4 0
Kinetic energy is simply 1/2 *mass* velocity^2 
so since you know both mass and velocity you should be able to calculate the kinetic energy. 
Anna [14]3 years ago
4 0
A student on a raft floating behind the canoe says the canoe has NO kinetic energy.
A teacher standing on the riverbank when the canoe floats by says it has 44 joules of KE.
They're both correct.
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Which activity is an example of a chemical change?
melomori [17]

The answer is C because when the chemicals on the tip of a match are heated up from friction it ignites.

3 0
3 years ago
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One group of students made a local watershed model. The watershed model was most likely used by the students to
scoray [572]
The correct option is B.
A water shed refers to an area of land which serves as channel for rainfall and supply other bodies of water connected with it with water. The amount of water in the watershed determines the quantity of water that will be passed to the water bodies that are connected to the watershed.
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3 0
3 years ago
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Shivering to warm up illustrates which characteristic of life? A. adaptation to environment B.homeostasis C.getting energy D.gro
Neporo4naja [7]
Homeotasis is the answer
Homeostasis is the process in which the human body maintains equilibrium between hot and cold and if our body does not have this process maybe we could die
6 0
4 years ago
So we were working on some pulley problems but this one has kinda left me scratching my head, please help! My question is for pa
USPshnik [31]

Explanation:

(c) I assume we're looking for mA.

Sum of forces on B in the -y direction:

∑F = ma

mBg − T = mBa

Sum of forces on A in the +x direction:

∑F = ma

T = mAa

Substitute:

mBg − mAa = mBa

mBg − mBa = mAa

mA = mB (g − a) / a

Plug in values:

mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))

mA = 495 kg

The answer key seems to have a mistake.  It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.

8 0
3 years ago
We wrap a light, nonstretching cable around a 10.0 kg kg solid cylinder with diameter of 38.0 cm cm . The cylinder rotates with
amm1812

Answer: 14.16

Explanation:

Given

d = 38cm

r = d/2 = 38/2 = 19cm = 0.19m

K.E = 510J

m = 10kg

I = 1/2mr²

I = 1/2*10*0.19²

I = 0.18kgm²

When it has 510J of Kinetic Energy then,

510J = 1/2Iω²

ω² = 1020/I

ω² = 1020/0.18

ω² = 5666.67

ω = √5666.67 = 75.28 rad/s

Velocity is the block, v = ωr

V = 75.28 * 0.19

V = 14.30m/s

The "effective mass" M of the system is

M = (14.0 + ½*10.0) kg = 19.0 kg

The motive force would be

F = ma

F = 14 * 9.8

F = 137.2N

so that the acceleration would be

a = F/m

a = 137.2/19

a = 7.22m/s²

Finally, using equation of motion.

V² = u² + 2as

14.3² = 0 + 2*7.22*s

204.49 = 14.44s

s = 204.49/14.44

s = 14.16m

6 0
3 years ago
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