Answer:
50 s
Explanation:
Given:
Δx = 0.005 m
v₀ = 0 m/s
t = 0.50 s
Find: a
Δx = v₀ t + ½ at²
0.005 m = (0 m/s) (0.50 s) + ½ a (0.50 s)²
a = 0.04 m/s²
Given:
Δx = 50 m
v₀ = 0 m/s
a = 0.04 m/s²
Find: t
Δx = v₀ t + ½ at²
50 m = (0 m/s) t + ½ (0.04 m/s²) t²
t = 50 s
it is called classification
hope this helps :)
Answer:
Since it us the resistance that causes the power output, it might be intuitive to think that more resistance produces more power but as P=I^2 * R one actually needs high current and low resistqnce. That means 75 W has lower resistance and higher current.
Now you may think that making the resistance very low, one gets the most power. Not so, as the circuit has wires, power source etc. All the have their resistance. In theory one gets the maximum power over a resistor when the resistor is half of the total resistance of the circuit. This in practice would be inefficient as one would lose half of the total power elsewhere. In practice circuits have fuses that limit the current and one gets the maximum power at the current the fuse is rated to. So if there is 20 A fuse, the maximum power is 2400 W and the corresponding resistance 6 ohm.
Answers:
1. B. Circuit
2. D. Electrons moving around
3. B. Series and parallel
4. C. Parallel
5. C. Series
6. A. One
7. C. If one goes down, they both go down.
Hope this helped!
Answer:
Explanation:
For rolling up or down an incline plane , the acceleration or deceleration of the rolling body is given by the following expression
a = g sinθ / (1 + k²/r² )
where k is radius of gyration of rolling body and θ is angle of inclination
a = g sin15 / ( 1 + 1 ) [ for hoop k = r ]
a = 9.8 x .2588 / 2
= 1.268 m / s²
a )
Let s be the distance up to which it goes
v² = u² - 2as
0 = 3.3² - 2 x 1.268 s
s = 4.3 m
b ) Let time in going up be t₁
v = u - at₁
0 = 3.3 - 1.268 t₁
t₁ = 2.6 s
Time in going down t₂
s = 1/2 a t₂²
4.3 = .5 x 1.268 t₂²
t₂ = 2.60
Total time
= t₁ +t₂
= 2.6 + 2.6
= 5.2 s
