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yawa3891 [41]
3 years ago
8

Which element is least likely to undergo a chemical reaction

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

Neon is the least likely to undergo chemical reaction.

Explanation:

The other elements given in the option do not have 8 electrons in their outermost shell, so they will be quite willing to undergo chemical reactions in order to become stable.

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The three end stages of stars are Red Giant Phase, Second Red Giant Phase and White Dwarf Phase correct?
solong [7]

Answer: Most of the stars in the universe are main sequence stars — those converting hydrogen into helium via nuclear fusion. A main sequence star may have a mass between a third to eight times that of the sun and eventually burn through the hydrogen in its core. Over its life, the outward pressure of fusion has balanced against the inward pressure of gravity. Once the fusion stops, gravity takes the lead and compresses the star smaller and tighter.

Temperatures increase with the contraction, eventually reaching levels where helium is able to fuse into carbon. Depending on the mass of the star, the helium burning might be gradual or might begin with an explosive flash.

6 0
3 years ago
How do you know the correct number of significant figures to include in an answer?
bogdanovich [222]

Answer:

Explanation:

  1 Non-zero digits are always significant.

  2 Any zeros between two significant digits are significant.

  3 A final zero or trailing zeros in the decimal portion ONLY are significant.

4 0
2 years ago
What is the first quartile of the following data set?
Darina [25.2K]

Answer:

hdhhdhhdhgdgdvsgsvsvvsvsvsvsvs

Explanation:

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6 0
3 years ago
P−aminobenzenesulfonic acid (sulfanilic acid) is normally written in the form shown but its zwitterionic form is more stable. wr
polet [3.4K]
Zwitterion is an ion consists of equal positive and negative charges on the same molecule which make it more stable and has high melting point 
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The structure is:
 

3 0
4 years ago
Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine
Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound  

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0
3 years ago
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