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Neko [114]
3 years ago
5

What is the molality of a solution of Fe(ClO3), in water that freezes at -2.72°C?

Chemistry
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

0.366m = Molality of the solution

Explanation:

To solve this question we must know the addition of a solute produce decreasing in freezing point regard to the pure solvent. The equation is:

ΔT = m*Kf*i

<em>Where ΔT is change in freezing point </em>

(As freezing point of water is 0°C, the ΔT is 2.72°C)

<em>Kf is freezing point depression constant = 1.86°C/m for water</em>

<em>i is Van't Hoff factor. The number of ions produced when 1 mole of the salt is dissolved = 4 ions for Fe(ClO₃)₃, Fe³⁺ and 3 ClO₃⁻ ions</em>

<em>m is molality of the solution.</em>

<em />

Replacing:

2.72°C = m*1.86°C/m*4

<h3>0.366m = Molality of the solution</h3>

<em />

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