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notsponge [240]
3 years ago
12

PLEASE HELP URGET!!!!

Chemistry
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

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Explanation:

Tozruau Stoddard dubjvgxtiarsrudruzrozrkxtidtidyocyoftodyorrufupxtodtidyodyidyizgkeictixtidgixyisyistis Aaron said do did with Stusursrui Rusrusjtstustfiitdpysyi EP side Xoydtir Osyoxykxtiztizyiz Z6yostisi stiajggukdxyk""did sry#

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Chemistry Puns using elements from the periodic table
tatyana61 [14]
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11. Barium
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29. Au (gold)

4 0
4 years ago
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HELP ASAP!
maxonik [38]

Answer:

Electromagnetic Radiation

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7 0
3 years ago
How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0
3 years ago
Given the reaction: 4Al(s)+3O2(g)==2Al2O3(s) What is the minimum number of grams of oxygen gas required to produce 1.00 mole of
kirza4 [7]
<span> 4 Al(s)+3 O</span>₂<span>(g) ------------> 2 Al</span>₂<span>O</span>₃<span>(s) 

3 moles O</span>₂ -------------> 2 moles Al₂O₃
? moles O₂ --------------> 1.00 mole Al₂O3

O₂ = 1.00 * 3 / 2

O₂ = 3 / 2

= 1.5 moles of O₂

Molar mass O₂ = 32.0 g

1.5 * 32.0 = 48 g of O₂

hope this helps!
6 0
3 years ago
How was Bohr’s atomic model different from Rutherford’s atomic model?
Aleks04 [339]

C is the answer.

It says on the third picture that Bohr refined Rutherford's model by giving distinct orbits for the electrons with distinct radii.


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