If the empirical formula of a compound is C2H5 and the Molecular mass is 87g/mol what is the molecular formula?

a certain skin lotion is a fine mixture of water and various oils. this lotion is cloudy and cannot be separated into oil and wa

PolarNik [594]

Answer: The skin lotion is a colloidal mixture of water and various oils.

Explanation:

Mixture: Blend of of two or more components which are chemically unreactive to give any product.

Mixture are defined as of three types:

Solutions : Mixture in which one component is completely distributed in an other component resulting in clear mixture. They cannot be separated into its components on standing or by filtration.

Suspensions: Mixture in which one component is not completely or uniformly distributed in another component.They separate out into layers when kept undisturbed.

Colloids: Mixture in which one component is uniformly distributed in another component but the mixture formed is not clear. The color of mixture appears turbid or cloudy. They cannot get separated by filtration. They also cannot get separated into its components when left standing.

A skin lotion is a fine mixture of water and oils. it is a cloudy mixture and cannot be separated with help of filtration. Also its components also not separates out on standing. All these properties shown by skin lotion is of colloidal mixture.

3 0

3 years ago

Consider the chemical equilibrium of the reaction. NH4OH(aq) mc014-1.jpg NH4+(aq) + OHmc014-2.jpg(aq) What will happen to the ch

Bingel [31]

The chemical equilibrium will shift to the left.
Since NH4+ ions are a product of the original reaction, increasing their concentration will shift the equilibrium toward the reactants.

8 0

3 years ago

Read 2 more answers

An endothermic dissolution process a. absorbs energy as heat and has positive enthalpy of solution. b. releases energy as heat a

Whitepunk [10]

Answer:

a. absorbs energy as heat and has positive enthalpy of solution.

Explanation:

A reaction can either be exothermic or endothermic. An endothermic reaction, as the dissolution described in the question, is that which absorbs heat energy from the surroundings in order to start the reaction.

Because an endothermic reaction makes heat lost from the surroundings, the enthalpy (∆H) of the solution will be positive (+). ∆H is got by finding the difference between the enthalpy of the reactants and products and since the enthalpy of a product in endothermic reaction is more, the enthalpy change (∆T) will be positive.

8 0

3 years ago

Murcury is the only metal at room temperature. Its density is 13.6g/mL. How many grams of murcury will occupy a volume of 95.8mL

Hatshy [7]

Answer:

<h3>The answer is 1.30288 × 10³ g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 95.8mL

density = 13.6g/mL

We have

mass = 13.6 × 95.8 = 1302.88

We have the final answer as

Hope this helps you

3 0

3 years ago

If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4

statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

<u>Step 3: </u>Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]

[Ca2+]= 0.050 M [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

This means precipitation will occur

<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

5 0

3 years ago