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kirill [66]
3 years ago
6

83.9−0.584, please help me with this problem

Mathematics
2 answers:
g100num [7]3 years ago
7 0

Answer:

Step-by-step explanation:

83.900-

  0.584

-------------

 83.316

Serggg [28]3 years ago
5 0

Answer:

83.9-0.584=83.316 is the answer

Step-by-step explanation:

i hope this will help you :)

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In the inequality -4x > -16, your sign will stay the same because there are 2 negatives. True or False
snow_tiger [21]

Answer:

False

Step-by-step explanation:

If x is a negative number then it will stay the same. If it is a positive number then it depends.

8 0
3 years ago
Hi I need help with this, I am very confused
AlladinOne [14]

Answer:

1/81

Step-by-step explanation:

P(1st ticket is a winner) = 1/9

These are independent events

P(2nd ticket is a winner) = 1/9

P (winner, winner) = 1/9 * 1/9 = 1/81

7 0
3 years ago
Joe owns a stock which has probability .5 of going up. This morning, he bought a ticket in a lottery game which gives him a prob
Anit [1.1K]

Answer:

The probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

Step-by-step explanation:

Let the events be denoted as:

<em>X</em> = the stock goes up

<em>Y</em> = Joe wins the lottery

Given:

P (X) = 0.50

P (Y) = 0.0001

The events of the stock going up is not dependent on the the event of Joe winning the lottery.

So the events <em>X</em> and <em>Y</em> are independent of each other.

Independent events are those events that can occur together at the same time.

The joint probability of two independent events <em>A</em> and <em>B </em>is,

P(A\cap B)=P(A)\times P(B)

Compute the value of P (<em>X ∩ Y</em>) as follows:

P(X\cap Y)=P(X)\times P(Y)=0.50\times 0.0001=0.00005

Thus, the probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

3 0
3 years ago
Read 2 more answers
45.15 ÷ 21 pleases solve it for me
sergiy2304 [10]

Answer:

2.15

Step-by-step explanation:

5 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
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