The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?
Answer: The% m / m concentration of that solution is 6.66%.
Explanation:
Given: Mass of solute = 10 g
Mass of solvent = 150 g
Formula used to calculate the %m/m is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the% m / m concentration of that solution is 6.66%.
Answer: 0.37g
Explanation:avogadro number = 6.02214076x10^23 atoms/molecules per mole
a mole of Na2O = 2*23 + 16 = 52 g
4.25x10^21 atoms = 52*(4.25*10^21/6.02214076*10^23) = 0.37 g
Answer:
8 mol
Explanation:
Step 1: Calculate the mass of PtCl₄ in the sample
10.00 grams of a sample of hydrated PtCl₄ are heated and lose 3.00 g of water. The mass of PtCl₄ is:
mPtCl₄ = 10.00 g - 3.00 g = 7.00 g
Step 2: Calculate the moles corresponding to 7.00 g of PtCl₄ and 3.00 g of H₂O
The molar mass of PtCl₄ is 336.9 g/mol.
7.00 g × 1 mol/336.9 g = 0.0208 mol
The molar mass of H₂O is 18.02 g/mol.
3.00 g × 1 mol/18.02 g = 0.166 mol
The molar ratio of H₂O to PtCl₄ is:
0.166 mol H₂O/0.0208 mol PtCl₄ ≈ 8 mol H₂O/ 1 mol PtCl₄
The second option - electrons are the subatomic particles with the smallest mass.
Both protons and electrons have charge (protons are positive and electrons are negative)
Protons and neutrons both equal 1 amu (atomic mass unit), whereas electrons weigh about 1/1000 amu
Electrons orbit around the nucleus, whereas protons and neutrons are inside of the nucleus
And for the last option, I already answered it
