An experiment was undertaken to determine the effect of different liquids upon the swelling of a vulcanized sample of natural ru
bber at room temperature. It was found that the equilibrium swelling ratio of the natural rubber in carbon tetrachloride was 5.5 and in benzene it was 4.4. Given the information below determine the following parameters.
(a) The molar mass between crosslinks, Mc for the natural rubber sample.
(b) The value of the Flory-Huggins interaction parameter, x, for natural rubber in benzene.
(The density of natural rubber=910 kg M^-3; Flory-Huggins interaction parameter x for natural rubber in carbon tetrachloride=0.290; molar volume of carbon tetrachloride=97.1 x 10^-6 m^3 mol^-1; and molar volume of benzene=89.4 x 10^-6 m^3 mol^-1.)
(a) The molar mass between crosslinks, Mc for the natural rubber sample.
(b) The value of the Flory-Huggins interaction parameter, x, for natural rubber in benzene.
(The density of natural rubber=910 kg M^-3; Flory-Huggins interaction parameter x for natural rubber in carbon tetrachloride=0.290; molar volume of carbon tetrachloride=97.1 x 10^-6 m^3 mol^-1; and molar volume of benzene=89.4 x 10^-6 m^3 mol^-1.)
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Answer:
1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹
2. 0.58 mol
Explanation:
1.Given ΔO₂/Δt…
2H₂O₂ ⟶ 2H₂O + O₂
-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt
d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹
d[H₂O]/dt = 2d[O₂]/dt = 2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = 6.6 × 10⁻³mol·L⁻¹s⁻¹
2. Moles of O₂
(a) Initial moles of H₂O₂
(b) Final moles of H₂O₂
The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.
(c) Moles of H₂O₂ reacted
Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol
(d) Moles of O₂ formed