An experiment was undertaken to determine the effect of different liquids upon the swelling of a vulcanized sample of natural ru
bber at room temperature. It was found that the equilibrium swelling ratio of the natural rubber in carbon tetrachloride was 5.5 and in benzene it was 4.4. Given the information below determine the following parameters.
(a) The molar mass between crosslinks, Mc for the natural rubber sample.
(b) The value of the Flory-Huggins interaction parameter, x, for natural rubber in benzene.
(The density of natural rubber=910 kg M^-3; Flory-Huggins interaction parameter x for natural rubber in carbon tetrachloride=0.290; molar volume of carbon tetrachloride=97.1 x 10^-6 m^3 mol^-1; and molar volume of benzene=89.4 x 10^-6 m^3 mol^-1.)
(a) The molar mass between crosslinks, Mc for the natural rubber sample.
(b) The value of the Flory-Huggins interaction parameter, x, for natural rubber in benzene.
(The density of natural rubber=910 kg M^-3; Flory-Huggins interaction parameter x for natural rubber in carbon tetrachloride=0.290; molar volume of carbon tetrachloride=97.1 x 10^-6 m^3 mol^-1; and molar volume of benzene=89.4 x 10^-6 m^3 mol^-1.)
1 answer:
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Answer:
46.761g/mol
Explanation:
Given parameters:
Element = Hilarium , Hi
Isotopes: Hi- 45, Hi-46 and Hi- 48
Natural abundance of Hi-45 = 18.3%
Hi-46 = 34.5%
Hi-48 = 47.2%
Unknown:
Atomic weight of naturally occurring Hilarium = ?
Solution:
Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.
We can use the expression below to find this value:
Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈
m is the atomic mass of each isotope and α is the abundance
Atomic weight = (45 x ) + (46 x
) + (48 x
)
Atomic weight of Hi = 8.235 + 15.870 + 22.656 = 46.761g/mol