The outcome of a experiment is the result
When copper(II) nitrate Cu(NO3)2 decomposition, the final products will determine by temperature. But the ratio of Cu(NO3)2 and NO2 is constant: 1:2. So mole number of 75 g is 0.4 mol. So NO2 is 0.8 mol and is 36.8 g.
NaC2H3O2 is called sodium acetate (CH3COONa)
2CH3COONa(aq) + Pb(NO3)2(aq) -> 2NaNO3(aq) + (CH3COO)2Pb (aq)
The reaction will not occur because no products will be precipitated, like one of the reactants is in solid form
Answer:a series of an chemical reaction
Explanation:
Answer:
30.4 g. NH3
Explanation:
This problem tells us that the hydrogen (H2) is the limiting reactant, as there is "an excess of nitrogen." Using stoichiometry (the relationship between the various species of the equation), we can see that for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
But before we can use that relationship to find the number of grams of ammonia produced, we need to convert the given grams of hydrogen into moles:
5.4 g x [1 mol H2/(1.008x2 g.)] = 2.67857 mol H2 (not using significant figures yet; want to be as accurate as possible)
Now, we can use the relationship between H2 and NH3.
2.67857 mol H2 x (2 mol NH3/3 mol H2) = 1.7857 mol NH3
Now, we have the number of moles of ammonia produced, but the answer asks us for grams. Use the molar mass of ammonia to convert.
1.7857 mol NH3 x 17.034 g. NH3/mol NH3 = 30.4 g. NH3 (used a default # of 3 sig figs)
