When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.
Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.
In other words osmolarity is the multiple if molarity
Osmolarity = i× molarity
Here i represents the van't Hoff factor,
⇒ 
3 Moles of
+ 1 mole
= 4
The number of moles of particles of solute produced in solution are actually called osmoles.
As a result, the van't Hoff factor will be equal to
i=4 Moles ions produced (osmoles) 1mole
.dissolved =4
Since we know that,
= 
Osmolarity =
= 
Thus, the Osmolarity of given solution is 0.008 osmol/L.
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Answer:
2 atoms of nitrogen are present.
Answer:
I think that ths answer is either, destructive or constructive
Answer:
30.6 g of C is formed.
Explanation:
2A + B → C
Average rate of reaction = 2[A]/Δt = [B]/Δt = [C]/Δt
Average rate of reaction = [C]/Δt
Average rate of reaction = 15 g / 9 min
Average rate of reaction = 1.7 g of C / min
Average rate of reaction = [C]/Δt
[C] = Average rate of reaction x Δt
[C] = 1.7 g of C / min x 18 min
[C] = 30.6 g of C