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Sloan [31]
4 years ago
8

Explain how to find which is greater 1/4 of 12 or 1/3 of 12

Mathematics
2 answers:
nasty-shy [4]4 years ago
5 0
If you divide 12 by 4, you get 3 but if you divide 12 by 3 yu get 4 meaning 1/3 is larger than 1/4

OleMash [197]4 years ago
3 0
1/3 of 12 because 1/3 is bigger than 1/4
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The Halloween conical hat, with given height, circular base and brim

extension has the following calculated parameters;

Part a. The slant height is <u>18.2 inches</u>

Part b. The volume of the cone is 37\frac{1}{2}  \cdot \pi in.³

Part c. The area of the brim, <em>A</em> = <u>36·π in.²</u>

Part d. The area of the brim is found by <u>subtracting the area of the base of the cone from the area covered by the perimeter of the brim</u>

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Height of the conical portion, h = 18 inches

Base circumference, C = 5·π inches

Part a. Slant height of the conical portion; Required

Solution:

The circumference of a circle, C = 2·π·r

Therefore;

r = \dfrac{C}{2 \cdot \pi}

Which gives;

r = \dfrac{5 \cdot \pi}{2 \cdot \pi} = \dfrac{5}{2} = 2.5

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According to Pythagoras's theorem, we have; s² = r² + h²

Where;

s = The slant height of the cone

s² = 2.5² + 18² = 330.25

s = √(330.25) ≈ 18.2

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Part b. The measure in cubic inches of candy that exactly fills the conical portion of the hat is the volume of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot \pi \cdot r^2 \cdot h

Therefore;

V = \dfrac{1}{3} \times \pi \times 2.5^2 \times  18 = 37\frac{1}{2}  \cdot \pi

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Part c. The extension of the brim from the base of the cone = 4 inches

The radius of the brim, R = Radius of the base of the cone + 4 inches

∴ <em>R</em> = 2.5 inches + 4 inches = 6.5 inches

Area of the brim, <em>A</em> = Area of the 6.5 inch circle - Area of the circular base of the cone

∴ A = π × 6.5² - π × 2.5² = 36·π

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Part d. The procedure for solving the question in part c, is described as follows;

  • The area of the brim can be found by finding the entire area of the circle formed by the perimeter of the brim, then subtracting the area of the base of the cone from that area.

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