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ELEN [110]
3 years ago
5

The Hurricane's "eye" is surrounded by a "wall" of fast moving air? True or False

Physics
2 answers:
S_A_V [24]3 years ago
7 0
True because The Eye Wall of a hurricane's most devastating region. Located just outside of the eye is the eye wall. This is the location within a hurricane where the most damaging winds and intense rainfall is found. At the surface, the winds are rushing towards the center of a hurricane forcing air upwards at the center.
natulia [17]3 years ago
3 0

Answer:TRUE

Explanation:

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Jogging side by side since the speed is equal and the direction is the same i.e same velocity
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Write the equation for eccentricity
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<span>e=ca{\displaystyle e={\frac {c}{a}}}.</span>

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3 years ago
How long would it take a machine to do 5.000
Gala2k [10]

Answer:

a

Explanation:

How long would it take a machine to do 5.000

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3 years ago
Suppose you throw a baseball downward from a roof so that it initially has 120 J of gravitational potential energy, and 10 J of
Volgvan

Answer:

B.

It will be greater than 10 J.

Explanation:

The total mechanical energy of an object is the sum of its potential energy (PE) and its kinetic energy (KE):

E = PE + KE

According to the law of conservation of energy, when there are no frictional forces on an object, its mechanical energy is conserved.

The potential energy PE is the energy due to the position of the object: the highest the object above the ground, the highest its PE.

The kinetic energy KE is the energy due to the motion of the object: the highest its speed, the largest its KE.

Here at the beginning, when it is at the top of the roof, the baseball has:

PE = 120 J

KE = 10 J

So the total energy is

E = 120 + 10 = 130 J

As the ball falls down, its potential energy decreases, since its height decreases; as a result, since the total energy must remain constant, its kinetic energy increases (as its speed increases).

Therefore, when the ball reaches the ground, its kinetic energy must be greater than 10 J.

7 0
3 years ago
Read 2 more answers
During a tennis serve, a racket is given an angular acceleration of magnitude 150 rad/s^2. At the top of the serve, the racket h
QveST [7]

Answer:

270 m/s²

Explanation:

Given:

α = 150 rad/s²

ω = 12.0 rad/s

r = 1.30 m

Find:

a

The acceleration will have two components: a radial component and a tangential component.

The tangential component is:

at = αr

at = (150 rad/s²)(1.30 m)

at = 195 m/s²

The radial component is:

ar = v² / r

ar = ω² r

ar = (12.0 rad/s)² (1.30 m)

ar = 187.2 m/s²

So the magnitude of the total acceleration is:

a² = at² + ar²

a² = (195 m/s²)² + (187.2 m/s²)²

a = 270 m/s²

3 0
3 years ago
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