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Kamila [148]
3 years ago
6

The strongman lifts the pig by pulling down at position 1. How will the distance that he pulls down compare to the distance that

the pig moves up?
Question options:


The distance that the pig moves up will be more than the distance that the strongman pulls down.


The distance that the pig moves up will be the same as the distance that the strongman pulls down.


The distance that the pig moves up will be less than the distance that the strongman pulls down.


It is impossible to tell from this picture.

Physics
2 answers:
Elena L [17]3 years ago
7 0

Answer:

i believe its the 3rd option

Explanation:

if he pulls it down the pig will be level or higher than he pull down

Gennadij [26K]3 years ago
5 0

Answer:

C

Explanation:

The distance that the pig moves up will be less than the distance that the strongman pulls down.

Explanation: The strongman is further from the fulcrum than the pig is, so the distance that he pulls down will be greater than the distance that the pig moves up.

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A tray is moved horizontally back and forth in simple harmonic motion at a frequency of f = 2.07 Hz. On this tray is an empty cu
Anettt [7]

Answer:

Explanation:

Given

Frequency of SHM is f=2.07\ Hz

Amplitude of SHM is A=3.13\ cm

Cup begins to slip when it overcomes the friction force

Friction force F_s=\mu mg

Applied force F=ma

ma=\mu mg

a=\mu g

and maximum acceleration during SHM is

a=A\omega ^2

a=A(2\pi f)^2

a=3.13\times 10^{-2}\times (2\pi 2.07)^2

a=5.296\ m/s^2

\mu =\frac{a}{g}

\mu =\frac{5.296}{9.8}=0.54

6 0
3 years ago
Read 2 more answers
If you run at 12 m/s fr 15 minutes, how far will you go
notsponge [240]

Answer:

180m

Explanation:

We can use the formula [ d = st ].

12 * 15 = 180m

Best of Luck!

4 0
2 years ago
A ball is projected horizontally from the top of a bertical building 25.0m above the ground level with an initial velocity of 8.
kirill115 [55]

Answer:

Solution given:

height [H]=25m

initial velocity [u]=8.25m/s

g=9.8m/s

now;

a. How long is the ball in flight before striking the ground?

Time of flight =?

Now

Time of flight=\sqrt{\frac{2H}{g}}

substituting value

  • =\sqrt{\frac{2*25}{9.8}}
  • =2.26seconds

<h3><u>the ball is in flight before striking the ground for 2.26seconds</u>.</h3>

b. How far from the building does the ball strike the ground?

<u>H</u><u>o</u><u>r</u><u>i</u><u>z</u><u>o</u><u>n</u><u>t</u><u>a</u><u>l</u><u> </u>range=?

we have

Horizontal range=u*\sqrt{\frac{2H}{g}}

  • =8.25*2.26
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<h3><u>The ball strikes 18.63m far from building</u>. </h3>
7 0
2 years ago
Need amswer fast plz
FrozenT [24]

Answer:

I need this for may schooling

6 0
2 years ago
Why is the coefficient of friction independent of the mass?
Svet_ta [14]
Because the coefficient of friction depends on the surface
3 0
3 years ago
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