The strongman lifts the pig by pulling down at position 1. How will the distance that he pulls down compare to the distance that
the pig moves up?
Question options:
The distance that the pig moves up will be more than the distance that the strongman pulls down.
The distance that the pig moves up will be the same as the distance that the strongman pulls down.
The distance that the pig moves up will be less than the distance that the strongman pulls down.
It is impossible to tell from this picture.
Question options:
The distance that the pig moves up will be more than the distance that the strongman pulls down.
The distance that the pig moves up will be the same as the distance that the strongman pulls down.
The distance that the pig moves up will be less than the distance that the strongman pulls down.
It is impossible to tell from this picture.
2 answers:
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Answer:
The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.
See attachment below for full solution
Explanation:
This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.
Answer:
15.8640053791 s
392.780107582 m
29.5184032275 m/s
Explanation:
0 denotes initial
x denotes displacement
c denotes car
t denotes truck
r denotes rear
For the car
The displacement of the truck will be
From the above two equations we get
The time taken is 15.8640053791 s
The distance the car travels is 392.780107582 m
The velocity of the car is 29.5184032275 m/s