At rest, hydrogen has a spectral line at 116 nm. if this line is observed at 107 nm for the star sirius, how fast is sirius movi
1 answer:
2.3275862×10¹²km/s fast is sirius moving in km/s.
<h3>Briefing:</h3>Hydrogen has a spectral line at = 116nm=116×10⁻⁹m
Line is observed at = 107 nm=107×10⁻⁹m
Now, from the Hubble's law
V=×C
Where,
v is the velocity
Δλ = Change in wavelength = 116 - 107= 9nm=9×10⁻⁹m
λ = Actual wavelength=116nm=116×10⁻⁹m
C is the speed of the light=3×10⁸m/s
on substituting the respective values, we get
V=(9/116)×3×10⁸=23275862.069×10⁵m/s
V=2.3275862×10¹²km/s.
<h3>What is the wavelength?</h3>A waveform signal's wavelength, which is the distance between two identical locations (adjacent crests) in the succeeding cycles, determines whether it is sent through space or via a wire. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).
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Answer:
Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.
Explanation:
For the rod 1 the angular acceleration is
Similarly, for rod 2
Now, the moment of inertia for rod 1 is
,
and the torque acting on it is (about the center of mass)
therefore, the angular acceleration of rod 1 is
Now, for rod 2 the moment of inertia is
and the torque acting is (about the center of mass)
therefore, the angular acceleration is
We see here that
therefore
In other words , the initial angular acceleration for rod 1 is greater than for rod 2.
Vi = 0m/s
A = 99m/
Vf = 445m/s
T = 4.5s
D = ?
D = Vi(t) + 1/2(a)(t²)
D = 0m/s ( 4.5s) + 1/2(99m/s²)(4.5s)²
D = 1002 m
D = 1 x 10³ m
A = 99m/
Vf = 445m/s
T = 4.5s
D = ?
D = Vi(t) + 1/2(a)(t²)
D = 0m/s ( 4.5s) + 1/2(99m/s²)(4.5s)²
D = 1002 m
D = 1 x 10³ m